Question

Use the graph of f(x) below to estimate the value of f ′(–2):

Answer 1

a. -1
b. 0
c. 1
d. 4

Answer 2

@mathmate @OOOPS @SolomonZelman @jim_thompson5910

Answer 3

Any idea?

Answer 4

We can take advantage on the options. :)

Answer 5

im supposed to find the derivative, f'(x), so that means finding the slope at the put (-2,5)

Answer 6

^i think

Answer 7

ok, to me, I cheat, hehehe...

Answer 8

so, with the tangent at -2, surely m \(\neq 0\), right? reject b)

Answer 9

hehehe... Let Mr. Jim guides you the professional way,

Answer 10

hint: notice how the graph has the roots x = -3 and x = 3. Use them to construct the algebraic function of the graph.

Answer 11

this is a parabola, so it's in the form ax^2 + bx + c

Answer 12

yah what u did i eliminated a and b right off the bat but i was then left w/ c & d....

got the parabola x^2-9 from the roots (x-3)(x+3)=0 but alas the parabola x^2-9 doesnt = the graph illustrated in the picture

Answer 13

notice the graph
notice its vertex
the parabola is going upside down, that means a leading negative term

\(\bf y=a(x-{\color{brown}{ h}})^2+{\color{blue}{ k}}\qquad vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})
\)

notice that to find the term "a", or leading coefficient
when x = \(\pm 3\) y = 0

Answer 14

x^2 - 9 is a parabola that opens upward

we want something that opens downward

Answer 15

you're close though

Answer 16

x^2+9

Answer 17

x^2 + 9 also opens upward

Answer 18

yes it does idk wht to do now

Answer 19

it seems you like using my cheating, hehehe...