Question

How would you solve for n?
n!/(n-2)! = 42

Answer 1

by definition

n! = n*(n-1)*(n-2)*...*3*2*1

we can rewrite that to say

n! = n*(n-1)*(n-2)!

Answer 2

so

\[\Large \frac{n!}{(n-2)!} = 42\]

\[\Large \frac{n(n-1)(n-2)!}{(n-2)!} = 42\]

\[\Large \frac{n(n-1)\cancel{(n-2)!}}{\cancel{(n-2)!}} = 42\]

\[\Large n(n-1) = 42\]

I'll let you finish

Answer 3

ok thank you

Answer 4

np