what can you conclude if a and b are nonzero integers such that a divides b and b divides a?
please helppp
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OpenStudy (wwwhhhaaattt?):
What do you think it is?
OpenStudy (anonymous):
its our homework in number theory and i cant anwer this question... its all about divisibility
OpenStudy (wwwhhhaaattt?):
Do you know your Times tables?
OpenStudy (anonymous):
yeah i knoww.
OpenStudy (wwwhhhaaattt?):
Ok, Then I want to see you try.
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OpenStudy (anonymous):
try? how?
OpenStudy (wwwhhhaaattt?):
Try.
OpenStudy (anonymous):
like all of em?
jimthompson5910 (jim_thompson5910):
a divides b means b = a*k for some integer k (basically 'a' is a factor of 'b')
b divides a means a = b*m for some integer m (basically 'b' is a factor of 'a')
OpenStudy (wwwhhhaaattt?):
Just try
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jimthompson5910 (jim_thompson5910):
so use the two equations
b = a*k
a = b*m
to help answer the question
jimthompson5910 (jim_thompson5910):
does that help @alesisaminion ?
OpenStudy (anonymous):
@jim_thompson5910 yeah :)) thanks a lot :)xx
jimthompson5910 (jim_thompson5910):
ok great, I'm glad it does
jimthompson5910 (jim_thompson5910):
tell me what you can conclude about m and k
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OpenStudy (anonymous):
@jim_thompson5910 look at your message
jimthompson5910 (jim_thompson5910):
you should have something along these lines in your steps/work
b = a*k
b = b*m*k ... replace 'a' with 'b*m'
b = b*(m*k)
b/b = [b*(m*k)]/b ... divide both sides by b
1 = m*k
m*k = 1
So I started with one equation, b = a*k, and ended up with m*k = 1.
If m*k = 1, then what must m and k be?
Hint: m and k are integers (they can be the same integer)