Double Integral.
\[\int\limits_{0}^{1}\int\limits_{0}^{\sqrt{1-x^2}} x dy dx\]
Convert to polar coordinates? I believe it can work here.
Maybe not, bleh, my multivar is slipping.
I think you are right.
Converting to polar....
I think another way is to rewrite the terms of integration to dx dy, instead of dy dx. That way, you'll get an x^2 term in the integral, and the square root can cancel out. But ofc, you'll have to redo the limits of integration
Sorry that took so long. It wouldn't let me press the 'post' button.
I am rusty on multivar too, but I don't think switching bounds will help here because circles are symmetrical with both y and x
That is true, but I just thought it would be another way to solve it, given that 'x' was the integrand
I may be wrong but evaluating it that way gave me zero for an answer.....which seems incorrect.
i got that too you can just integrate this as is; let me make sure that give zero too
I didn't get 0, I got a nice rational number.
i got zero every way can we see your work iPwn?
Sorry. (1/2)x*2sqrt(1-x^2)
Unfortunately, my work was putting it in a calculus caluator lol.
yes i got a rational number too :P
Don't you change the terms from dy dx to r dr d(theta), or something like that?
I got an answer just by integrating as is
Ahh
you can do a u-sub after the inner integral
Thank you both (;
welcome!
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