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Mathematics 21 Online
OpenStudy (anonymous):

Double Integral.

OpenStudy (anonymous):

\[\int\limits_{0}^{1}\int\limits_{0}^{\sqrt{1-x^2}} x dy dx\]

OpenStudy (ipwnbunnies):

Convert to polar coordinates? I believe it can work here.

OpenStudy (ipwnbunnies):

Maybe not, bleh, my multivar is slipping.

OpenStudy (anonymous):

I think you are right.

OpenStudy (anonymous):

Converting to polar....

OpenStudy (ipwnbunnies):

I think another way is to rewrite the terms of integration to dx dy, instead of dy dx. That way, you'll get an x^2 term in the integral, and the square root can cancel out. But ofc, you'll have to redo the limits of integration

OpenStudy (ipwnbunnies):

Sorry that took so long. It wouldn't let me press the 'post' button.

OpenStudy (turingtest):

I am rusty on multivar too, but I don't think switching bounds will help here because circles are symmetrical with both y and x

OpenStudy (ipwnbunnies):

That is true, but I just thought it would be another way to solve it, given that 'x' was the integrand

OpenStudy (anonymous):

I may be wrong but evaluating it that way gave me zero for an answer.....which seems incorrect.

OpenStudy (turingtest):

i got that too you can just integrate this as is; let me make sure that give zero too

OpenStudy (ipwnbunnies):

I didn't get 0, I got a nice rational number.

OpenStudy (turingtest):

i got zero every way can we see your work iPwn?

OpenStudy (anonymous):

Sorry. (1/2)x*2sqrt(1-x^2)

OpenStudy (ipwnbunnies):

Unfortunately, my work was putting it in a calculus caluator lol.

OpenStudy (turingtest):

yes i got a rational number too :P

OpenStudy (ipwnbunnies):

Don't you change the terms from dy dx to r dr d(theta), or something like that?

OpenStudy (turingtest):

I got an answer just by integrating as is

OpenStudy (ipwnbunnies):

Ahh

OpenStudy (turingtest):

you can do a u-sub after the inner integral

OpenStudy (anonymous):

Thank you both (;

OpenStudy (turingtest):

welcome!

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