Find m<1 and m<3 in the kite. The diagram is not to scale.
m1 = m<DAC = .... m3+m<DAC=90 m3+17=90 m3=?
what is the value of the angles formed by intersection of AC and DB? in a kite these are always
because the diagonals of a kite intersect at right angles angle 2 = 90 degress and angle next to it = 90 degrees so because of the property 3 angles of a triangle add up to 180 degrees angle 3 = 180 - (17 + 90) = 180 - 129 = ? degrees
51?
yes
correct
Do you need me to list the answers?
umm...? okay
a. m<1 =18, m<3 =73. b. m<1 =73, m<3 =73. c. m<1 =73, m<3 = 17 d. m<1 =17, m<3 = 17
what did you get?
I haven't gotten anything, because I don't know what to do. The only thing I did was what you told me to add.
recheck the options given
well the answer is either C or D
I'm not sure either.
@pooja195 do you know?
im not sure :/
Alrighty, it's okay I'm stuck on it too.
There is a big difference in C and D
Do you know it Radar if so may you please help me?
@radar
I think it's A @radar
Choice A. while not exactly correct is the best answer. The two upper triangles are congruent. Angle m1 is actually 17 degrees, not 18.
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