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Chemistry 13 Online
OpenStudy (anonymous):

@ParthKohli i need help

OpenStudy (anonymous):

@austin11111 @sammixboo @bohotness calculate the concentration of CO2 in a soft drink after the bottle is opened and equilibriates at 25C under a CO2 partial pressure of 0.003 atm.

OpenStudy (anonymous):

@ParthKohli @austin11111 calculate the concentration of CO2 in a soft drink after the bottle is opened and equilibriates at 25C under a CO2 partial pressure of 0.003 atm.

OpenStudy (anonymous):

@madinaxxx calculate the concentration of CO2 in a soft drink after the bottle is opened and equilibriates at 25C under a CO2 partial pressure of 0.003 atm.

OpenStudy (anonymous):

@madinaxxx know how to do it

OpenStudy (anonymous):

@madinaxxx please

OpenStudy (anonymous):

@madinaxxx hello stop stalling

OpenStudy (anonymous):

@abb0t know how to solve it please

OpenStudy (anonymous):

@abb0t calculate the concentration of CO2 in a soft drink after the bottle is opened and equilibriates at 25C under a CO2 partial pressure of 0.003 atm.

OpenStudy (madinaxxx):

\[1.0\times10^{-5}M\]

OpenStudy (anonymous):

@madinaxxx how do you solve it step by step please

OpenStudy (anonymous):

@abb0t alculate the concentration of CO2 in a soft drink after the bottle is opened and equilibriates at 25C under a CO2 partial pressure of 0.003 atm.

OpenStudy (anonymous):

@abb0t help please

OpenStudy (anonymous):

@madinaxxx @abb0t hello help

OpenStudy (anonymous):

@abb0t help me please

OpenStudy (abb0t):

You're missing some information here I believe. You can use henry's law for this.

OpenStudy (madinaxxx):

OpenStudy (madinaxxx):

try this it might help

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