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Chemistry 7 Online
OpenStudy (madinaxxx):

If 5.2 g of K2CrO4 and enough AgNO3 to completely react are mixed, how many grams of KNO3 will be produced? 2AgNO3 + K2CrO4 = Ag2CrO4 + 2KNO3

OpenStudy (madinaxxx):

@Abhisar

OpenStudy (abhisar):

What is the molar mass of K2CrO4 and KNO3?

OpenStudy (madinaxxx):

120g/mol?

OpenStudy (abhisar):

Got it?

OpenStudy (madinaxxx):

K2CrO4=194g/mol KNO3=101g/mol 295g/mol

OpenStudy (abhisar):

no you don't need to add them up..

OpenStudy (madinaxxx):

oh ok

OpenStudy (abhisar):

now, see the equation. According to it, 2 moles of KNO3 is produced from 1 mole of K2CrO4.

OpenStudy (abhisar):

ryt??

OpenStudy (madinaxxx):

yeah

OpenStudy (abhisar):

now convert 5.2 K2CrO3 into moles

OpenStudy (madinaxxx):

183g/mol

OpenStudy (abhisar):

5.2/194 =?

OpenStudy (madinaxxx):

.0268

OpenStudy (abhisar):

yes, sice 1 mole of it produces two moles of KNO3, .268 moles of it will produce .536 moles of KNO3. Finally convert this into grams and that will be your answer.

OpenStudy (madinaxxx):

convert .536 moles into grams?

OpenStudy (abhisar):

yep, use molar mass of KNO3 this time.

OpenStudy (madinaxxx):

I dont know how to do that...

OpenStudy (abhisar):

1 mole=101 gram => .536 moles = .536*101 grams

OpenStudy (madinaxxx):

54.136 g?

OpenStudy (abhisar):

yes

OpenStudy (madinaxxx):

thats the answer?

OpenStudy (abhisar):

yes

OpenStudy (madinaxxx):

Thank You :)))

OpenStudy (abhisar):

welcome

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