Find f if f′′(x)=sinx+cosx, f′(0)=4, and f(0)=5 find f(x) ------------------------------ I got the integral and (double?) integral: -cosx+sinx and -sinx-cosx respectivly. I have no cluee how to solve the rest here. I got it with another similar problem but how do i do it with 2 integrals?
you are missing the constants which you find like before
\[f'(x)=-\cos(x)+\sin(x)+C\] and you need \(C\) via \[f'(0)=4\]
hey misty sorry im not so good at these lol so i would need to to plug (0) into x and set it equal to 4 right?
yes, just like the other one no need to be sorry though
so i would have 5=C correct? for the first part?
would this mean I would have -sinx-cosx+5x=f(x)?
\[4=-1+C\\ C=5\] ok good
and yes but don't forget the +C you have to do this dog an pony show again
\[f(x)=-\cos(x)-\sin(x)+5x+C\] etc etc
i have a question
why don't you use this one?
lol I think I will
but one more question
So I ended up with 6=C for f(x) but I feel that is eerily wrong
lets check
\[f(x)=-\cos(x)-\sin(x)+5x+C\] \[f(0)=-1+C=5\\ C=6\] what is wrong with that ?q
...Nothing? i think?
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