Find f if f′′(x)=sinx+cosx, f′(0)=4, and f(0)=5
find f(x)
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I got the integral and (double?) integral: -cosx+sinx and -sinx-cosx respectivly. I have no cluee how to solve the rest here. I got it with another similar problem but how do i do it with 2 integrals?
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OpenStudy (misty1212):
you are missing the constants which you find like before
OpenStudy (misty1212):
\[f'(x)=-\cos(x)+\sin(x)+C\] and you need \(C\) via
\[f'(0)=4\]
OpenStudy (anonymous):
hey misty sorry im not so good at these lol
so i would need to to plug (0) into x and set it equal to 4
right?
OpenStudy (misty1212):
yes, just like the other one
no need to be sorry though
OpenStudy (anonymous):
so i would have 5=C correct? for the first part?
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OpenStudy (anonymous):
would this mean I would have -sinx-cosx+5x=f(x)?
OpenStudy (misty1212):
\[4=-1+C\\
C=5\] ok good
OpenStudy (misty1212):
and yes but don't forget the +C
you have to do this dog an pony show again
OpenStudy (misty1212):
\[f(x)=-\cos(x)-\sin(x)+5x+C\] etc etc
OpenStudy (misty1212):
i have a question
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OpenStudy (misty1212):
why don't you use this one?
OpenStudy (anonymous):
lol I think I will
OpenStudy (anonymous):
but one more question
OpenStudy (anonymous):
So I ended up with 6=C for f(x) but I feel that is eerily wrong
OpenStudy (misty1212):
lets check
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OpenStudy (misty1212):
\[f(x)=-\cos(x)-\sin(x)+5x+C\]
\[f(0)=-1+C=5\\
C=6\] what is wrong with that ?q