Hey, I need to solve the inequality:
2x+3<2(x+3)
0<0
So the answer is (-infinity;+infinity)? Or there is no Real solutions to this equation? It is a bit confusing for me, because how 0 can be a smaller number than 0 (according to the problem)?
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OpenStudy (kamille):
@hartnn
OpenStudy (kamille):
to this inequality*,sorry,I am still sleeping;D
hartnn (hartnn):
its not 0<0
distribute 2 to (x+3)
for simplifying
\(2(x+3)\)
and it is not same as 2x+3
OpenStudy (kamille):
uhh:o sorry! Then I know how to solve. Whats about this one:
6x+7>2(3x+4)
6x-6x>8-7
0x>1
(hopefully no arithmetic mistakes now;D)
OpenStudy (kamille):
nah, I dont know still how to solve that one too;D
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OpenStudy (jhannybean):
Do the same thign.
hartnn (hartnn):
0>1
never true, right?
so no solution :)
OpenStudy (kamille):
and the first one is 0x<3 so x e (-infinity;+infinity)?
hartnn (hartnn):
thats right :)
OpenStudy (kamille):
because 0 is always smaller than 3?
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