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Mathematics 16 Online
OpenStudy (kamille):

Hey, I need to solve the inequality: 2x+3<2(x+3) 0<0 So the answer is (-infinity;+infinity)? Or there is no Real solutions to this equation? It is a bit confusing for me, because how 0 can be a smaller number than 0 (according to the problem)?

OpenStudy (kamille):

@hartnn

OpenStudy (kamille):

to this inequality*,sorry,I am still sleeping;D

hartnn (hartnn):

its not 0<0 distribute 2 to (x+3) for simplifying \(2(x+3)\) and it is not same as 2x+3

OpenStudy (kamille):

uhh:o sorry! Then I know how to solve. Whats about this one: 6x+7>2(3x+4) 6x-6x>8-7 0x>1 (hopefully no arithmetic mistakes now;D)

OpenStudy (kamille):

nah, I dont know still how to solve that one too;D

OpenStudy (jhannybean):

Do the same thign.

hartnn (hartnn):

0>1 never true, right? so no solution :)

OpenStudy (kamille):

and the first one is 0x<3 so x e (-infinity;+infinity)?

hartnn (hartnn):

thats right :)

OpenStudy (kamille):

because 0 is always smaller than 3?

OpenStudy (kamille):

thankyouu:}

hartnn (hartnn):

welcome ^_^

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