help please?? :c
Find the range of f(x) = -x + 4 for the domain (-3, -2, -1
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OpenStudy (anonymous):
Domain is all the x values, and Range is all the why values. Substitute x with the set you have. Example: f(-3) = -(-3) + 4
OpenStudy (anonymous):
*y values.
OpenStudy (anonymous):
I don't understand this at all
OpenStudy (anonymous):
f(x) = -x + 4 is the same as y = -x + 4
OpenStudy (anonymous):
the choices are
7, 6 5, 3
-7, -6, -5, 3
7, 6, 5, 4
-7,-6,-5,-4
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OpenStudy (anonymous):
Example: Domain: {-3, -2, -1, 0} --- Range: {?}
f(-3) = -(-3) + 4 = (3) + 4 = 7
Range for -3 is 7.
OpenStudy (anonymous):
It's best if you try it out. It'll allow you to get the grip on things :)
OpenStudy (anonymous):
f(x) = -x + 4
Keep replacing x with the value provided in the domain until you have all range.
OpenStudy (anonymous):
Yes :)
OpenStudy (anonymous):
-(x) = -1 (x)
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OpenStudy (anonymous):
okay so I just tried.. would it be
7, 6 5, 3
OpenStudy (anonymous):
so 7, 6, 5, 4 ?
OpenStudy (anonymous):
Correct :)
OpenStudy (anonymous):
incorrect >.<
OpenStudy (anonymous):
oh okay
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OpenStudy (anonymous):
@NeedHelp__ You sure? I'm assuming there was a 0 since you have 4 numbers in your options.
OpenStudy (anonymous):
yeah there was but I need help with another problem if you could help :)
OpenStudy (anonymous):
Evaluate f(x) = -x2 - 4 for x = -3
a. -9
b. -13
c. 1
d. -1
OpenStudy (anonymous):
yes I do
OpenStudy (anonymous):
f(x) = -1[(-3)(-3)] - 4
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OpenStudy (anonymous):
solve what's in the parenthesis ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
wouldn't that cancel out?
OpenStudy (anonymous):
Nope, (-3)(-3) = 9 so:
f(x) = -1[9] - 4
OpenStudy (anonymous):
a negative multiplied by a negative = a positive.
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OpenStudy (anonymous):
oh yeah >.< okay
OpenStudy (anonymous):
Since exponents is just a means of saying how many times a number multiply by itself, all even exponents of a negative number will give a positive. All odd exponents will give a negative number.
OpenStudy (anonymous):
\[-x ^{2} = x; -x ^{3} = -x\]
OpenStudy (anonymous):
So what's the answer?
OpenStudy (anonymous):
-9?
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OpenStudy (anonymous):
Go on: f(x) = -1[9] - 4
OpenStudy (anonymous):
1?
OpenStudy (anonymous):
f(x) = -9-4
OpenStudy (anonymous):
Oh.. >.< -13
OpenStudy (anonymous):
correct :)
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OpenStudy (anonymous):
evaluate F(x) = -2x - 5 for x = 3
a. -11
b. 11
c. 1
d. -6
OpenStudy (anonymous):
same as before :) Replace x with 3 then PEMDAS
OpenStudy (anonymous):
I think its -6 but im sure im wrong
OpenStudy (anonymous):
Nope
OpenStudy (anonymous):
I mean if you just mean -2x then yes
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OpenStudy (anonymous):
11?
OpenStudy (anonymous):
f(x) = -6-5
OpenStudy (anonymous):
oh -11
OpenStudy (anonymous):
correct :)
OpenStudy (anonymous):
evaluate f (x) = 1/4x for x = -5
A. -4/5
B. -1 1/4
C. -1/20
D. 20
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OpenStudy (anonymous):
Does the equation look like so: \[f(x) = \frac{ 1 }{ 4x }?\]
OpenStudy (anonymous):
yes the x is separate though
OpenStudy (anonymous):
Like this: \[f(x) = \frac{ 1 }{ 4 }x\]
OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Multiply x with 1/4.
OpenStudy (anonymous):
Basically do this: Since all whole numbers, such as 1, 2, 3, are simply \[\frac{ a }{ 1 }\] then when multiplying a whole number with a fraction the equation would look like so:\[\frac{ 1 }{ 4 } (\frac{ x }{ 1 }) = \frac{ 1 }{ 4 } (\frac{ -5 }{ 1 }) = \frac{ 1(-5) }{ 4(1) }\]
OpenStudy (anonymous):
-4/5?
OpenStudy (anonymous):
You got them backwards.
OpenStudy (anonymous):
-5/4 sorry
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OpenStudy (anonymous):
Yup.
OpenStudy (anonymous):
but that's not an option
OpenStudy (anonymous):
it is :)
OpenStudy (anonymous):
no the only one that has those numbers is A which is -4/5 >.<
OpenStudy (anonymous):
Improper fractions are rational numbers where the numerator is greater than the denominator. Improper fractions can be rewritten as a mixed number –an integer plus a proper fraction. An improper fraction represents a number greater than one.
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