Question

Help please..what is the vertex form of the equation?
y=x^2+12x-4
Pleasee help!

Answer 1

a(x – h)^2 + k is vertex form

Answer 2

what

Answer 3

I can't see what that says

Answer 4

a(x – h)^2 + k

Answer 5

a(x - h)^2 + k

Answer 6

Where h,k is the vertex

Answer 7

Yes

Answer 8

factors of -4 that add up to 12 are -4 and 16

Answer 9

y = x^2 + 12x - 4

y = x^2 + 12x + (36 - 36) - 4

Answer 10

y = (x^2 + 12x + 36) - 36 - 4

y = (x + 6)^2 - 40

Answer 11

@swagmaster47

Answer 12

@mathmate is this right what I did?

Answer 13

What you did is right, but not yet complete!

Answer 14

You need the vertex, which is (h,k) in
\(y=(x-h)^2+k\)
Interpret the values of h and k and you're done!

Answer 15

ohh ok but wait I just realized that there was a negative sign in front of the x

Answer 16

Exactly, you have just avoided a very common mistake, good job.
So what do you find for the vertex (h,k) ?

Answer 17

y = -x^2 + 12x - 4
y= - [ (x^2 -12x +36)- 36 +4]
y= - ( x- 6)^2 -32
( x- 6)^2 = - y-32

Answer 18

\(y= - [ (x^2 -12x +36)- 36 \color{red}{-}4] \)
What you had was correct, just need to interpret h and k, from
\(y = (x + 6)^2 - 40 \) and \(y=(x-h)^2+k\)
The vertex is at (h,k).

Answer 19

there is no initial negative in
\(y= [ (x^2 -12x +36)- 36 \color{red}{-}4]\)

Answer 20

oh ok

Answer 21

So what do you get for h and k?

Answer 22

Compare the two equations which are equivalent, then try to deduce the value of h and k:
\(y = (x + 6)^2 - 40 ~~\equiv~~ y=(x-h)^2+k\)

Answer 23

Now it works

Answer 24

Do you see better this way? I have a problem with computer loading as well, it's very slow, don't know if it's me or the server.

Answer 25

Yes I do! :) thank you

Answer 26

You're welcome! :)
BTW, what are the values you found for h & k?

Answer 27

they were -8 and 4

Answer 28

Wait...
(x+6)=(x-h) so what is h?

Answer 29

4

Answer 30

:(
\(x+6\ne x-4\)

Answer 31

6? Idk sorry :(

Answer 32

\(x+6\ne x-6\)
You need to do something!

Answer 33

I see is it 12>

Answer 34

\(x+6 = x-(-6)\), so h=-6
is that ok?

Answer 35

Yes

Answer 36

Now you need to find k!
Compare both sides of the equation, find k so that both sides will be equal.
\(y = (x + 6)^2 - 40 ~~\equiv~~ y=(x-h)^2+k\)

Answer 37

The server or my computer is very slow. I will take a break!