Question

HELP PLEASE GET MEDALS

Answer 1

@micahwood50 @bruhhh

Answer 2

@jazzy688

Answer 3

@undeadknight26

Answer 4

@Abhisar @Coolsector @loomely @ofmice&men @nermaljean99 @Abhisar @Dbzfan836

Answer 5

I was thinking it's SAS.

Answer 6

I will show you this:

Answer 7

So no matter how long BF and CE are, their intersection would form equivalent BC and EF.

Answer 8

So you have:
2 sets of equivalent (diagonally laying) sides.
they are:
BD=DF
DC=DC (remember that bisect means right in the middle, and given that they
bisect each other, that means that the point of intersection is the middle of both bisecting segments)

Answer 9

And then, in addition to this, as I showed by my pictures,
BC=EF (with the above [correct] conditions that are applied) and regardless of the lengths CE and BF will this will be true (that BC=EF).

Answer 10

go carefully over what I am saying, and take your time if needed.

Answer 11

Yes, I think BC=EF because their the same right?

Answer 12

yes, because the intersection point of two diagonal segments BF and CE is in the middle of both of this segments...

Answer 13

So you have 3 congruent sides.

Answer 14

So it will be SSS?

Answer 15

yes

Answer 16

very good!