The formula for continuously compounded interest on a principal investment P at a given interest rate r over time t in years is given by A = Pe^rt. You have deposited $12,000 in an account that pays 4.15% interest, compounded continuously. How long will it take for your initial investment to grow six times its original worth? Round your answer to the nearest tenth.
@satellite73 could you help me Im not so good with compound interest S:
would this be 43.2 years?
\[\large A=Pe^{rt}\ ..............(1)\] If we divide both sides of (1) by P we get: \[\large \frac{A}{P}=e^{rt}\ ............(2)\] In the question it is given that A/P = 6, and r expressed as a decimal is 0.0415. Plugging these values into (2) gives: \[\large 6=e^{0.0415t}\ ...........(3)\] Now you just need to solve (3) to find the value of t.
See this is where it comes difficult for me Because I dont understand how to get an exponent by itself
Take natural logs of both sides of (3).
so if natural then would it be 6e?
im kinda new to log S:
nvm so ln6=0.0415t?
Your equation: \[\large \ln 6=0.0415t\] is correct. Now you need to divide both sides of the equation by 0.0415 to find the value of t in years.
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