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Mathematics 10 Online
undeadknight26 (undeadknight26):

Heys can some one help me with this? I dunno wudda do...

undeadknight26 (undeadknight26):

-2x - 2y = 26 -x + 3y = -3

undeadknight26 (undeadknight26):

Needs to be solved using distribution guys!

OpenStudy (solomonzelman):

distribution is same thing as substitution. \(\large\color{slate}{ -2x - 2y = 26 }\) \(\large\color{slate}{ -x + 3y = -3 }\) you rearrange one of the equation for 1 variable (in terms of the other variable), and (substitute into the other equation:)

OpenStudy (solomonzelman):

if you need an example, ask me, and I will give you one (or two and even three if you would like to).

undeadknight26 (undeadknight26):

I think i understand now mates...thanks :D

OpenStudy (solomonzelman):

I will put up an answer check, and will make a point about a method efficiency.

OpenStudy (solomonzelman):

\(\scriptsize\color{ slate }{\scriptsize{\bbox[5pt, blueviolet ,border:2px solid blueviolet ]{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ }}}\) Just to verify the answer, and show the efficiency of elimination. \(\large\color{slate}{ -2x - 2y = 26 }\) \(\large\color{slate}{ -x + 3y = -3 }\) multiplying the 2nd equation times -2 \(\large\color{slate}{ -2x - 2y = 26 }\) \(\large\color{slate}{ 2x - 6y = 6 }\) adding them: \(\large\color{slate}{ 0x - 8y = 32 }\) so, \(\large\color{slate}{ y = -4 }\) (then, solving for x is not hard) \(\scriptsize\color{ slate }{\scriptsize{\bbox[5pt, blueviolet ,border:2px solid blueviolet ]{~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ }}}\)

undeadknight26 (undeadknight26):

mhmm me unda stand I just spent a few minutes poking around my lesson finding more information lol

OpenStudy (solomonzelman):

sure:)

OpenStudy (solomonzelman):

btw, there are another 2 methods to solve a linear system (in general). graphing the equations (and intersection of the 2 is a solution) using matrix ( to set a matrix to [1 0 | x ] [0 1 | y ] )

OpenStudy (solomonzelman):

I guess though, they choose a method for you, and not the most efficient one-:( but you can do it! good luck!

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