What is the slope-intercept form of the function that contains the point (6, 2) and has a slope of 3? y = x + @bruhhh
slope intercept is y-y1=m(x-x1) so y-2=3(x-6) :)
huh?
so you mean y=3x+6?
Well if they want just the form of it, no simplifying or anything, then you'd leave it how I typed it. They just wanted you to plug the numbers in to form it
it says y=___x+___
so i can't put y-2
Oh I gotchya, then they do want you to simplify it. y-2=3(x-6) y-2=3x-18 y=3x-16
Does that make sense?
they don't want me to simlify it
i can't put y-2=3(x-6)
That's really the only answer that would be right though if they have it set up as the normal equation of a line
Oh I meant, put y=3x-16 instead lol
I was just showing how they got from the point-slope form to the equation of a line, does that make sense at all?
how you get 16 and the minus sign?
So plugging in for point-slope gave us y-2=3(x-6) distributing the 3 to the x & 6 gives us y-2=3x-18 Then to get the y by itself, you add the 2 to both sides of the equal sign, giving us y=3x-16
as i said it can't be y-2=3(x-6) because that's not the equation
its y=___x+___
Yes so it's now y=3x-16
oh
thanks
Lol it's the y-intercept can be negative if the value is negative. Hope that helped!!
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