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Biology 8 Online
OpenStudy (anonymous):

Will FAN & MEDAL!!!

OpenStudy (anonymous):

Moth color is determined by a single gene with two alleles displaying complete dominance. The dominant color is black, and the recessive is white. A moth population of 1,000 has the following color frequency:

OpenStudy (anonymous):

Moth Color Black = 734 White = 266 Determine the genotype frequency of the F1 population following the cross of a homozygous dominant individual with a homozygous recessive individual. Next, determine genotype frequency of the F2 population when two heterozygous members of the F1 generation are crossed. Explain whether this population is in equilibrium based on the Hardy-Weinberg principle.

OpenStudy (anonymous):

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OpenStudy (anonymous):

@Secret-Ninja @Jhannybean @YanaSidlinskiy @Coolsector @CausticSyndicalist @winsteria

OpenStudy (anonymous):

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OpenStudy (anonymous):

Sorry for mass tag but I REALLY NEED HELP!!!

OpenStudy (anonymous):

I don't take biology sorry

OpenStudy (anonymous):

it's ok

OpenStudy (jordanloveangel):

Lets Break this down a bit Using B to represent the dominant and w to represent the recessive the homozygous crossing in a punnet square looks like this B B w Bw Bw w Bw Bw so all F1 offspring will be heterozygous Black. When theses are inbred between themselves the punnet square looks like this B w B BB Bw w Bw ww So 25% of your population will have the phenotype Black homozygous 50% of your population will have the phenotype Black heterozygous 25% of your population will have the phenotype White homozygous the genotype is just how the genes are expressed so 75% of your population will have the black phenotype and white will be 25%. so 25% of 266 will be your answer for the recessive and 75% of 2344 will be the dominant genotype frequency hope this helps :)

OpenStudy (anonymous):

So all F1 offspring will be heterozygous Black? What about F2? @jordanloveangel

OpenStudy (jordanloveangel):

So far, using the equation P^2 2pq q^2 = 1 and P q = 1, I have: p (frequency of dominant allele) = .4842 p^2 (frequency of homozygous dominant individuals) = .2344 q (recessive allele) = .5157 q^2 (frequency of homozygous recessive individuals) = .266 ("given" from the chart) 2pq (heterozygous individuals) = .4994

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