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Help please What is the percentage of nitrogen in N2O4? Show all calculations leading to an answer.
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To find the answer take the mass of all of the nitrogen atoms in the compound, divide by the molar mass, then multiply by 100 to express the answer as a percent. \[\color{green}{\frac{2 \times 14.0}{(2 \times 14.0) + (4 \times 16.0 )} \times 100}\]
around 30% ?
Closer to 29.2 % (3 significant figures)
could you explain that? Just so I have a clear understanding. Thanks.
I know about significant figures but in this equation im having a hard time figuring it out
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