MEDAL!!! The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the triangle?
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OpenStudy (jhannybean):
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OpenStudy (jhannybean):
For special right triangles, we can apply The Pythagorean Theorem, which states, \((\text{hypotenuse})^2 = (\text{leg 1})^2 + (\text{leg 2})^2\)
OpenStudy (alexandervonhumboldt2):
by pyth theorem x^2+3^2=11^2
OpenStudy (jhannybean):
Or it can rather be written as \(c^2 = a^2+b^2\) where c is the hypotneuse, and a and b are the legs.
Now if we are given the length of the hypotenuse and a leg of a triangle, we can rearrange our equation to solve for the leg of the triangle
OpenStudy (alexandervonhumboldt2):
x^2=121-9
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OpenStudy (alexandervonhumboldt2):
x=sqrt(112)
OpenStudy (jhannybean):
Therefore, \(11^2 = 3^2 +x^2 \implies x = \sqrt{11^2 -3^2}\)
OpenStudy (jhannybean):
Now just solve for x and you will find the length of the missing leg :)
OpenStudy (anonymous):
so its |dw:1420575723087:dw|
OpenStudy (alexandervonhumboldt2):
yes
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