Question

Verify the identity! Problem attached :)

Answer 1

\[\cot (x-\frac{ \pi }{ 2 }) = -\tan~x\]

Answer 2

@freckles

Answer 3

apply : cot = cos / sin
then apply cos (a-b) = cos a cos b+ sina sin b
sin (a-b) = sin a cos b- sinb cosa
you can get the right hand side

Answer 4

@ooops would that look like\[\frac{ \cos }{ \sin })(x-\pi/2)\] on the left?

Answer 5

\(cot (x -\pi/2) =\dfrac{cos (x-\pi/2)}{sin(x-\pi/2)}\)
for numerator, apply what I said above with a = x, b = pi/2
the advantage is cos pi/2 =0, sin pi/2 =1

Answer 6

Oh! This makes alot of sense thanks!

Answer 7

yw