Question

PLEASE HELP ME

Answer 1

ifg you want i can tell you what i got so far

Answer 2

@quin100 @satellite73 @DanJS

Answer 3

k

Answer 4

5x - y = 27
2x + 3y = -13

Answer 5

multiply the first equation by 3 first...

Answer 6

5x – y = 27
5x – y + y = 27 + y
5x = 27 + y
5x – 27 = 27 + y – 27
Y=


3 (5x – 27) = 3.5x – 3 * 27 = 15x – 81
2x + 3(5x – 27) = -13
2x + 15x – 81 = -13

Answer 7

thats what i got so far

Answer 8

15x - 3y = 81
2x + 3y = -13
-------------

The first equation was multiplied by 3, now add the two equations together

Answer 9

notice the Y cancels out , (-3Y + 3Y) = 0Y

Answer 10

was mine right? so far

Answer 11

hmm, looks like you were kinda there in the first equation. You were solving for Y. That is another way you can do this. Solve Both for Y, then set them equal.

Answer 12

This way is easier i think ... Just multiply the first equation by 3, then add them together

Answer 13

i got help before and they quite on me because they had to go sadly

Answer 14

quit*

Answer 15

15x - 3y = 81 First equation x3
2x + 3y = -13
-------------------------- add them together
17x + 0y = 68

Answer 16

I multiplied the first equation by 3, so that when you add them , the Y term goes to ZERO

Answer 17

now you are left with

17x = 68

x = 68/17 = 4

Answer 18

Put x = 4 into one of the equations, and solve for y

Answer 19

so...
15x - 3y = 81
2x + 3y = -13
17x + 0y = 68
17x = 68 x = 68/17 = 4

Answer 20

start off from mine than end with your right?

Answer 21

@DanJS

Answer 22

Right, you multiplied the first equation through by 3, so that the Y term would be -3, and when you add the equation, the Y variable cancels out,

looks good so far, now use that x = 4 in one of the equations and find Y

2x + 3y = -13 ; x = 4

2(4) + 3y = -13

8 + 3y = -13 subtract 8 from both sides

3y = -13 - 8 = -21

divide both sides by 3

y = -21/3

y = -7

so overall x=4 and y = -7

Answer 23

so...

5x – y = 27
5x – y + y = 27 + y
5x = 27 + y
5x – 27 = 27 + y – 27
15x – 3 = 81
2x + 3y = -13
17x + 0y = 68
17x = 68x = 68/17=
4
2x + 3y = -3
X = 4
2 (4) + 3y = -3
8 + 3y = -13 subtract 8 from both sides
3y = -13 – 8 = -21 divide both sides by 3
Y = -21/3
Y = -7
X = 4 and y = -7


and thats the end of that equation @DanJS

Answer 24

yeah looks like exactly what i typed, cept jumbled up together..

Answer 25

tag me in a neq question if you want to do another prob

Answer 26

new*

Answer 27

what happened to ....


3 (5x – 27) = 3.5x – 3 * 27 = 15x – 81
2x + 3(5x – 27) = -13
2x + 15x – 81 = -13

... is that the end of my how question

Answer 28

is that the answer to my whole question**

Answer 29

when it says solve, they just want x=# and y=#, the values for the unknown variables x and y

Answer 30

ok

Answer 31

Graphically , each of those equations is a line on the XY-plane.
The solution x = 4 and y=-7, is the point where the lines cross each other.
(x,y) = (4,-7)

Answer 32

so im done ? @DanJS

Answer 33

i can link a graph of this prob if you would like

Answer 34

that would be great thanks !

Answer 35

sorry, this site is a piece of crap and lagging like crazy.. give me one min

Answer 36

You can see the equations for the lines on the left, and the intersection point is the solution (4,-7)

Answer 37

are we done with the whole thing now? and thanks @DanJS

Answer 38

yes, solve the system, means, find that point where the lines cross.
(x,y) = (4,-7) x = 4 and y = -7

Answer 39

you are welcome, anytime