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OpenStudy (anonymous):
Titration: Can someone help me understand this concept. Sample question below. If 10.0mL of 25.0 mol/L NaOH(aq) is added to 30.0mL of 0.17 mol/L HOCN(aq), what is the pH of the resulting solution?
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OpenStudy (anonymous):
what do you think the answer is?
OpenStudy (anonymous):
answer is 3.74 I need explanation how to get it
OpenStudy (anonymous):
@wio @SolomonZelman @Abhisar @AndrewTheCookie @funfuse2 @Hotchellerae21 @bibby @bohotness
OpenStudy (anonymous):
@AndrewTheCookie @dan815 @CausticSyndicalist @Teddyiswatshecallsme @TheRaggedyDoctor
OpenStudy (bohotness):
Yes
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