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Mathematics 9 Online
OpenStudy (anonymous):

sec 45 degrees=?

OpenStudy (anonymous):

one over the cosine of 45 degrees

OpenStudy (jhannybean):

\[\sec(x) = \frac{1}{\cos(x)}\]

OpenStudy (solomonzelman):

|dw:1420596658214:dw| \(\large\color{slate}{ \sec(45^\circ)=s\sqrt{2}/s=? }\)

OpenStudy (anonymous):

do you know what \[\cos(45^\circ)\] is ?

OpenStudy (solomonzelman):

guess that is a better start sate...

OpenStudy (jhannybean):

Okay i am bad at maaking the little degree symbol -.-

OpenStudy (anonymous):

\circ

OpenStudy (anonymous):

\[x^\circ\]

OpenStudy (jhannybean):

\[\cos(45^\circ) =\frac{1}{\cos(45^\circ)}\]

OpenStudy (jhannybean):

there we go.

OpenStudy (anonymous):

nice

OpenStudy (anonymous):

cos 45=1/1\[\sqrt{2}\] on a 45 45 90 triangle

OpenStudy (anonymous):

i menat 1/1 square root of 2

OpenStudy (anonymous):

i think that was supposed to be \(\frac{1}{\sqrt2}\) right?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

flip it

OpenStudy (anonymous):

square root of 2

OpenStudy (anonymous):

yup

OpenStudy (jhannybean):

\[\cos(45^\circ) =\frac{1}{\cos(45^\circ)} = \frac{1}{\dfrac{\sqrt{2}}{2}} = \frac{2}{\sqrt{2}}=\sqrt{2}\]

OpenStudy (jhannybean):

Good job.

OpenStudy (anonymous):

thank you so much! and this will apply to a 45 45 90 triangle right?

OpenStudy (anonymous):

|dw:1420597109507:dw|

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