What is the equation of the graphed linear model?
\(\huge \rlap{\bbox[2.9pt, ,border:6.8px solid #2aacd7 ]{\Huge\color{blueviolet}{\rm \fbox{Welcome}}}}\hspace{127pt}\huge \rlap{\bbox[3.3pt, ,border:7px solid #2aacd7 ]{\Huge\color{blueviolet}{\rm \fbox{to}}}}\) \(\huge \color{blueviolet}{\heartsuit^{\LARGE \heartsuit^{\Large \heartsuit}}}\) \(\huge \color{blueviolet}{\heartsuit^{\LARGE \heartsuit^{\Large \heartsuit}}}\) \(\huge \huge \rlap{\bbox[5pt, ,border:8px solid #2aacd7 ]{\Huge\color{#84c73c}{\rm \fbox{OpenStudy}}}}\) Do you ahve an image of this graph?
Thanks! Give me a second
Ok, so they give you 2 points, (4, 16) and (6, 12)
With those 2 points, use the slope formula.
ok thxs:)
So, what is the slope?
@bibby Im on this question right now can you help me?
use the slope f ormula
how do I do that?
y=mx+b where b is the y intercept and m is the slope \(m=\dfrac{y_2-y_1}{x_2-x_1}\)
take any 2 points from the corners of the rectangle
okay give me a sec
it makes more sense to pick from the 2 points on the line though (4, 16) and (6, 12)
okay I got 8/10
show your work, I got something else
|dw:1424677148347:dw|
Join our real-time social learning platform and learn together with your friends!