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Mathematics 15 Online
OpenStudy (anonymous):

What is the equation of the graphed linear model?

OpenStudy (anonymous):

\(\huge \rlap{\bbox[2.9pt, ,border:6.8px solid #2aacd7 ]{\Huge\color{blueviolet}{\rm \fbox{Welcome}}}}\hspace{127pt}\huge \rlap{\bbox[3.3pt, ,border:7px solid #2aacd7 ]{\Huge\color{blueviolet}{\rm \fbox{to}}}}\) \(\huge \color{blueviolet}{\heartsuit^{\LARGE \heartsuit^{\Large \heartsuit}}}\) \(\huge \color{blueviolet}{\heartsuit^{\LARGE \heartsuit^{\Large \heartsuit}}}\) \(\huge \huge \rlap{\bbox[5pt, ,border:8px solid #2aacd7 ]{\Huge\color{#84c73c}{\rm \fbox{OpenStudy}}}}\) Do you ahve an image of this graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

Thanks! Give me a second

OpenStudy (sleepyjess):

Ok, so they give you 2 points, (4, 16) and (6, 12)

OpenStudy (sleepyjess):

With those 2 points, use the slope formula.

OpenStudy (anonymous):

ok thxs:)

OpenStudy (sleepyjess):

So, what is the slope?

OpenStudy (chunkymonkay):

@bibby Im on this question right now can you help me?

OpenStudy (bibby):

use the slope f ormula

OpenStudy (chunkymonkay):

how do I do that?

OpenStudy (bibby):

y=mx+b where b is the y intercept and m is the slope \(m=\dfrac{y_2-y_1}{x_2-x_1}\)

OpenStudy (bibby):

take any 2 points from the corners of the rectangle

OpenStudy (chunkymonkay):

okay give me a sec

OpenStudy (bibby):

it makes more sense to pick from the 2 points on the line though (4, 16) and (6, 12)

OpenStudy (chunkymonkay):

okay I got 8/10

OpenStudy (bibby):

show your work, I got something else

OpenStudy (chunkymonkay):

|dw:1424677148347:dw|

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