Question

sqrt11/(50m) how do you do this radical to see if its in simplified form? Need help please

Answer 1

\[\sqrt{\frac{ 11 }{ 50 }}\]
right?
for a start you can split it up like this
\[\frac{\sqrt{11}}{\sqrt{50}}\]

Answer 2

ok yea

Answer 3

then what do I do

Answer 4

well you can't break down 11 but you might be able to break down 50 let me show you.

Answer 5

no I have not im trying to learn all this stuff gets confusing to me

Answer 6

oh I need to edit that I messed up let me fix it so i can explain =)

Answer 7

Ok so what I did here was break down 50 into its multiples
25*2=50
you can break down 2 any more but you can 25
5*5= 25 so that is how I got that

Answer 8

we know that the sqrt of 25 is 5 so you can pull it out writing the fraction like this
\[\frac{\sqrt{11}}{5\sqrt{2}}\]

Answer 9

you can rewrite it any way you want here is another way
\[\frac{\sqrt{\frac{11}{2}}}{5}\]

Answer 10

do you understand? If not I'd be happy to answer any of your questions

Answer 11

a little bit so that means with the 11 its not in simplified form cause there is no way of breaking that down

Answer 12

11 is prime.
After prime factorization: 11

50 is composite.
After prime factorization: 5*5*2

\[\frac{ \sqrt[2]{11} }{ \sqrt[2]{50} }=\frac{ \sqrt[2]{11} }{ \sqrt[2]{2*5*5} }=\frac{ \sqrt[2]{11} }{ 5\sqrt[2]{2} }\]

Then you should rationalize ...

\[\frac{ \sqrt[2]{11} }{ 5\sqrt[2]{2} }*\frac{ \sqrt[2]{2} }{ \sqrt[2]{2} }=\frac{ \sqrt[2]{11*2} }{ 5\sqrt[2]{2*2}}=\frac{ \sqrt[2]{22} }{ 5\sqrt[2]{4} }=\frac{ \sqrt[2]{22} }{ 5*2 }=\frac{ \sqrt[2]{22} }{ 10 }\]