Question

Write an equation of a line that is perpendicular to the line y = 5x + 1 and contains the point (-10,2).

Answer 1

@Daniellelovee
@Littlebird

Answer 2

perpendicular lines have slopes that are negative reciprocals of eachother

Answer 3

So y = - 1/5x + 1

Answer 4

Do I have to change the y intercept like last time?

Answer 5

Yes, because they want you to include a specific point

Answer 6

52 = b?

That feels wrong >.>

Answer 7

I did

2 = 5(-10) + b
2 = -50 + b

Add 50 to both sides

52 = b

Answer 8

Put the 2 in for y and the -10 in for x

Answer 9

Remember that you have to change the slope to -1/5

Answer 10

y = -1/5x + 52

Answer 11

No, before you find the y-intercept, change the slope

Answer 12

OOOOH , my bad

Answer 13

So it would:

2 = -1/5(-10) + b

Then

2 = 2 + b

Subtract 2 from both sides

b = 0

Answer 14

Then final answer would be:

y = -1/5x + 0

Answer 15

yes, but in your real answer, you shouldn't have to write out the + 0

Answer 16

Yeah, I thought so ;P