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Algebra 13 Online
OpenStudy (anonymous):

can someone pls help me with this question

OpenStudy (anonymous):

OpenStudy (anonymous):

f(x) = 28 + 5x

OpenStudy (anonymous):

Since 28 is the value of 5 CDs, to get a total of 10 cds, the value of x must 5.

OpenStudy (anonymous):

how do i find C(x)=

OpenStudy (perl):

C(x) is the same as f(x)

OpenStudy (anonymous):

C(x) <- Is called a function. Function can be named differently so long the format is similar to f(x).

OpenStudy (anonymous):

so i multiply 28 and 10 by 5

OpenStudy (anonymous):

nope, 28 is already 5 cds, since you you'd only need 5 more to make 10, x = 5

OpenStudy (anonymous):

*you would

OpenStudy (anonymous):

oh so for C(x)= i put 5

OpenStudy (anonymous):

Nope, C(x) is the function. So C(x) = f(x) = 28 + 5x

OpenStudy (anonymous):

-23 = 23x

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

May I ask how you got 23x?

OpenStudy (anonymous):

or -1.

OpenStudy (anonymous):

5=28+23x 5=28+23x +28 +28 -23 = 23 x -1

OpenStudy (anonymous):

5 CDs = $28 + $23 multiplied by the number of additional CDs?

OpenStudy (anonymous):

5=28+23x 5=28+23x -28 -28 -23 = 23 x -1

OpenStudy (anonymous):

sorry wrong sign

OpenStudy (anonymous):

You presented the equations wrong. 10 CDs should be on left of your equation. 10 CDs = $28 + $5x Since $28 = 5 CDS, x = number of additional CDS.

OpenStudy (anonymous):

Got it?

OpenStudy (anonymous):

think so

OpenStudy (anonymous):

Recycled CDs Inc., offers a choice of 5 used CDs for $28 ($28 = 5 CDS), with each additional CD costing $5 (5x). Write a cost function for purchasing 5 or more CDS (C(x) = 28 + 5x). What will the cast of buying 10 CDs be? Let x represent the number of CDs over 5. (Since 28 is equal to 5 cds, then x = additional cds. The value of 10 cds is C(x) = 28 + 5x)

OpenStudy (anonymous):

In Parenthesis are the translation from English to algebra.

OpenStudy (anonymous):

with x = 5. Since 10-5 = x.

OpenStudy (anonymous):

C(x)=3

OpenStudy (anonymous):

28 + 5x?

OpenStudy (anonymous):

28+5x(5) 28+25x 28+25x -25 -25 x= 3

OpenStudy (anonymous):

Substitute x for 5

OpenStudy (anonymous):

C(x) = 28 + 5(x); x = 5 C(x) = 28 + 5(5) C(x) = 28 + 25 = 53

OpenStudy (anonymous):

What you did is linear equation, you're currently doing functions.

OpenStudy (anonymous):

how do functions differ from linear equation

OpenStudy (anonymous):

C(x) = has the same value of x

OpenStudy (anonymous):

y = has the value solving the equation

OpenStudy (anonymous):

C(x) = y

OpenStudy (anonymous):

If you were using y then y = 28 + 5x

OpenStudy (anonymous):

y = 10, x = 5.

OpenStudy (anonymous):

so i put C(x)=5 then the total cost for the 10 cds is

OpenStudy (anonymous):

10 = 28 + 5(5)

OpenStudy (anonymous):

Typo

OpenStudy (anonymous):

C(x) = cost y = number of cds.

OpenStudy (anonymous):

53 dollars

OpenStudy (anonymous):

y = 5 + x => total number of cds. C(x) = 28 + 5x => total cost of cds.

OpenStudy (anonymous):

28 = 5 cds x = number of additional cds 5x = total cost of the additional cds.

OpenStudy (anonymous):

am i right C(x)=5 and !0 CDs cost $53

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

|dw:1420614565398:dw|

OpenStudy (anonymous):

Since you're looking for the cost (y), and cost is dependent to the number of cds (x). You graph would look like that.

OpenStudy (anonymous):

thanks very much i dont have to graph this question

OpenStudy (ajspeller):

c(x) = 5(x-5) + 28 c(10) = 5(10-5) + 28 c(10) = 5(5) + 28 c(10) = 25 + 28 c(10) = 53 c(5) = 5(5-5) + 28 c(5) = 5(0) + 28 c(5) = 0 + 28 c(5) = 28

OpenStudy (anonymous):

^okay, that's way better then mine.

OpenStudy (anonymous):

thx a lot so this is what my answers should look like

OpenStudy (perl):

C(x) = 5x +28

OpenStudy (perl):

where x = # cds in addition to the first 5 cds

OpenStudy (anonymous):

oh so it should look like this

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

C(x) should look like 5(x-5) + 28

OpenStudy (anonymous):

5x-25+28 right

OpenStudy (anonymous):

nope.

OpenStudy (anonymous):

That's what you should put in the box

OpenStudy (anonymous):

The first box is asking for an expression. "5(x-5) + 28" this is an expression. You're not solving for x.

OpenStudy (anonymous):

oooooh this

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you were saying it the whole time but i thought you mean it was an equation oooh im dumb af

OpenStudy (anonymous):

thank you very much

OpenStudy (anonymous):

"C(x) = 5(x-5) + 28" => Function (a type of equation) "y = 5(x-5) + 28" => Equation (linear)

OpenStudy (anonymous):

Anything with a "=" is an equation, anything with ">, <, etc" is an Inequality.

OpenStudy (anonymous):

oook thanks a lot

OpenStudy (anonymous):

anything without an "=" or ">, <, etc" is an expression.

OpenStudy (anonymous):

now i understand

OpenStudy (anonymous):

Your welcome :D

OpenStudy (anonymous):

btw, you better close the ask :)

OpenStudy (perl):

@ganeshie8 It says in the directions 'let x represent the number of cds over 5' , therefore I assumed x stands for the number of additional cds to the first 5, so I got C(x) = 5x + 28 The other user sadworld has C(x) = 5(x-5) + 28 would you like to arbitrate here

OpenStudy (perl):

also another user got 5(x-5) + 28

OpenStudy (anonymous):

so what i put as final answer was wrong

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