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OpenStudy (anonymous):
OpenStudy (anonymous):
f(x) = 28 + 5x
OpenStudy (anonymous):
Since 28 is the value of 5 CDs, to get a total of 10 cds, the value of x must 5.
OpenStudy (anonymous):
how do i find C(x)=
OpenStudy (perl):
C(x) is the same as f(x)
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OpenStudy (anonymous):
C(x) <- Is called a function. Function can be named differently so long the format is similar to f(x).
OpenStudy (anonymous):
so i multiply 28 and 10 by 5
OpenStudy (anonymous):
nope, 28 is already 5 cds, since you you'd only need 5 more to make 10, x = 5
OpenStudy (anonymous):
*you would
OpenStudy (anonymous):
oh so for C(x)= i put 5
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OpenStudy (anonymous):
Nope, C(x) is the function. So C(x) = f(x) = 28 + 5x
OpenStudy (anonymous):
-23 = 23x
OpenStudy (anonymous):
-1
OpenStudy (anonymous):
May I ask how you got 23x?
OpenStudy (anonymous):
or -1.
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OpenStudy (anonymous):
5=28+23x
5=28+23x
+28 +28
-23 = 23 x
-1
OpenStudy (anonymous):
5 CDs = $28 + $23 multiplied by the number of additional CDs?
OpenStudy (anonymous):
5=28+23x
5=28+23x
-28 -28
-23 = 23 x
-1
OpenStudy (anonymous):
sorry wrong sign
OpenStudy (anonymous):
You presented the equations wrong. 10 CDs should be on left of your equation.
10 CDs = $28 + $5x
Since $28 = 5 CDS, x = number of additional CDS.
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OpenStudy (anonymous):
Got it?
OpenStudy (anonymous):
think so
OpenStudy (anonymous):
Recycled CDs Inc., offers a choice of 5 used CDs for $28 ($28 = 5 CDS), with each additional CD costing $5 (5x). Write a cost function for purchasing 5 or more CDS (C(x) = 28 + 5x). What will the cast of buying 10 CDs be? Let x represent the number of CDs over 5. (Since 28 is equal to 5 cds, then x = additional cds. The value of 10 cds is C(x) = 28 + 5x)
OpenStudy (anonymous):
In Parenthesis are the translation from English to algebra.
OpenStudy (anonymous):
with x = 5. Since 10-5 = x.
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OpenStudy (anonymous):
^okay, that's way better then mine.
OpenStudy (anonymous):
thx a lot so this is what my answers should look like
OpenStudy (perl):
C(x) = 5x +28
OpenStudy (perl):
where x = # cds in addition to the first 5 cds
OpenStudy (anonymous):
oh so it should look like this
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
C(x) should look like 5(x-5) + 28
OpenStudy (anonymous):
5x-25+28 right
OpenStudy (anonymous):
nope.
OpenStudy (anonymous):
That's what you should put in the box
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OpenStudy (anonymous):
The first box is asking for an expression. "5(x-5) + 28" this is an expression. You're not solving for x.
OpenStudy (anonymous):
oooooh this
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
you were saying it the whole time but i thought you mean it was an equation oooh im dumb af
OpenStudy (anonymous):
thank you very much
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OpenStudy (anonymous):
"C(x) = 5(x-5) + 28" => Function (a type of equation)
"y = 5(x-5) + 28" => Equation (linear)
OpenStudy (anonymous):
Anything with a "=" is an equation, anything with ">, <, etc" is an Inequality.
OpenStudy (anonymous):
oook thanks a lot
OpenStudy (anonymous):
anything without an "=" or ">, <, etc" is an expression.
OpenStudy (anonymous):
now i understand
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OpenStudy (anonymous):
Your welcome :D
OpenStudy (anonymous):
btw, you better close the ask :)
OpenStudy (perl):
@ganeshie8 It says in the directions 'let x represent the number of cds over 5' , therefore I assumed x stands for the number of additional cds to the first 5,
so I got C(x) = 5x + 28
The other user sadworld has C(x) = 5(x-5) + 28
would you like to arbitrate here