Question

A metalworker has a metal alloy that is 20% copper and another alloy that is 55% copper. How many kilograms of each alloy should the metalworker combine to create 100kg of a 48% copper alloy?

The metal worker should use how many kilograms of the metal alloy that is 20% copper and how many kilograms of the metal alloy that is 55% copper?

Answer 1

1 kg of alloy(1) 20% coppre
1 kg of alloy (2) 55% copper
copper % of these 2 kg = (20+55)/2=37.5%

Answer 2

this is a hint... (alloy (1) mass * alloy(1) copper%)+(alloy(2)mass*(alloy(2) copper%)/total mass=48 copper %

Answer 3

mass (1)+mass(2)=100

Answer 4

(m1*%1+M2%2)=48
m1+m2=100
solve for either m1 or m2 then put it back in eq(1)

Answer 5

(20m1+55m2)/(m1+m2)=48
(20m1+55m2)/100=48
20m1+55m2=4800
m1+m2=100
m1=100-m2
20(100-m2)+55m2=4800
2000-20m2+55m2=4800
35m2=4800-2000=4600
m2=4600/35=131.428

Answer 6

isnt this a system of equations
A metalworker has a metal alloy that is 20% copper and another alloy that is 55% copper. How many kilograms of each alloy should the metalworker combine to create 100kg of a 48% copper alloy?

x + y = 100
.20x + .55y = .48 * 100

Answer 7

where x = # kg of 20% copper alloy
y = # kg of 55% copper alloy

Answer 8

according to wolfram
x = 20, y = 80
http://www.wolframalpha.com/input/?i=solve++x+%2B+y+%3D+100%2C++.20x+%2B+.55y+%3D+.48+*+100+