The vertex is tip of the parabola..in this case its (0, 0).
OpenStudy (igreen):
We can use the equation to find the vertex:
\(\dfrac{-b}{2a}\)
Our equation is in the form of \(y = ax^2 + bx + c\).
Therefore:
a = 1
b = 6
Plug them in:
\(\dfrac{-6}{2(1)}\)
Can you solve that?
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OpenStudy (anonymous):
nvm -3
OpenStudy (anonymous):
-6 divided 2
OpenStudy (anonymous):
i'll try to fill in y
OpenStudy (anonymous):
\[y=(-3)^{2} + 6 (3) -2\]
OpenStudy (anonymous):
would that be right ?
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OpenStudy (igreen):
Yes, so the x-value of the vertex is -3.
Now we can plug -3 for x in the equation to find the y-value:
\(y = x^2 + 6x - 2\)
\(y = -3^2 + 6(-3) - 2\)
Yep, you got it.
OpenStudy (anonymous):
19 - 18 - 2= -11
OpenStudy (igreen):
Now just solve to find 'y'.
OpenStudy (anonymous):
How would I do that now
OpenStudy (igreen):
Lol, you just did..
So your answer is (-3, -11)
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