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Mathematics 18 Online
OpenStudy (anonymous):

Find the vertex of the parabola. Will post bellow

OpenStudy (anonymous):

\[y= x ^{2} + 6x -2\]

OpenStudy (anonymous):

What is a parabola?

OpenStudy (igreen):

A parabola is like a U shaped graph..here's an example: https://www.desmos.com/calculator/ibfe9hnwgg

OpenStudy (igreen):

The vertex is tip of the parabola..in this case its (0, 0).

OpenStudy (igreen):

We can use the equation to find the vertex: \(\dfrac{-b}{2a}\) Our equation is in the form of \(y = ax^2 + bx + c\). Therefore: a = 1 b = 6 Plug them in: \(\dfrac{-6}{2(1)}\) Can you solve that?

OpenStudy (anonymous):

nvm -3

OpenStudy (anonymous):

-6 divided 2

OpenStudy (anonymous):

i'll try to fill in y

OpenStudy (anonymous):

\[y=(-3)^{2} + 6 (3) -2\]

OpenStudy (anonymous):

would that be right ?

OpenStudy (igreen):

Yes, so the x-value of the vertex is -3. Now we can plug -3 for x in the equation to find the y-value: \(y = x^2 + 6x - 2\) \(y = -3^2 + 6(-3) - 2\) Yep, you got it.

OpenStudy (anonymous):

19 - 18 - 2= -11

OpenStudy (igreen):

Now just solve to find 'y'.

OpenStudy (anonymous):

How would I do that now

OpenStudy (igreen):

Lol, you just did.. So your answer is (-3, -11)

OpenStudy (anonymous):

o thank you very much for helping me out :)

OpenStudy (igreen):

No problem.

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