Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

Dean drank 1280 mL of water on Monday. On Tuesday he increased his water intake by 82%. How much water did Dean drink on Tuesday?

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

sure,

OpenStudy (anonymous):

he is drinking additional 82% to his 100%. (100% is 1280 mL) so he is taking 182% of the 1280mL 182% of something , >>> something times 1.82.

OpenStudy (anonymous):

\(\large\color{r}{ 1280{\tt~ mL}~ ~\cdot~~1.82 }\)

OpenStudy (anonymous):

btw, with the same additional intake every day, you will have: \(\large\color{r}{ f(x)=1280(1.82)^x }\), as your function, for any day x, with whater f(x)

OpenStudy (anonymous):

I mean of course it is not a real case though...

OpenStudy (anonymous):

he can't be drinking that much water... like going to this function, there will be some constraint for x.

OpenStudy (anonymous):

anyway... I gave you the needed assitance

OpenStudy (anonymous):

You find 82% of 1280.

OpenStudy (anonymous):

Then you add that to 1280.

OpenStudy (anonymous):

no need, why? multiply times 1.82

OpenStudy (anonymous):

So multiply 0.82 x 1280, then after you get the value of that, add it to 1280.

OpenStudy (anonymous):

Where did you get 1.82 from?

OpenStudy (anonymous):

but that is longer. It would be simpler to multiply times 1.82

OpenStudy (anonymous):

because 100% is the entire percent (which is 1820) he is taking additional 82% \, that means he is taking 182% percent of 1820. so multiply 1820 times 1.82 (comverting 182% to decimal)

OpenStudy (anonymous):

I think I said that already., @AnswerMyQuestions

OpenStudy (anonymous):

Long story short its 2329.6.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!