Dean drank 1280 mL of water on Monday. On Tuesday he increased his water intake by 82%. How much water did Dean drink on Tuesday?
@iGreen
sure,
he is drinking additional 82% to his 100%. (100% is 1280 mL) so he is taking 182% of the 1280mL 182% of something , >>> something times 1.82.
\(\large\color{r}{ 1280{\tt~ mL}~ ~\cdot~~1.82 }\)
btw, with the same additional intake every day, you will have: \(\large\color{r}{ f(x)=1280(1.82)^x }\), as your function, for any day x, with whater f(x)
I mean of course it is not a real case though...
he can't be drinking that much water... like going to this function, there will be some constraint for x.
anyway... I gave you the needed assitance
You find 82% of 1280.
Then you add that to 1280.
no need, why? multiply times 1.82
So multiply 0.82 x 1280, then after you get the value of that, add it to 1280.
Where did you get 1.82 from?
but that is longer. It would be simpler to multiply times 1.82
because 100% is the entire percent (which is 1820) he is taking additional 82% \, that means he is taking 182% percent of 1820. so multiply 1820 times 1.82 (comverting 182% to decimal)
I think I said that already., @AnswerMyQuestions
Long story short its 2329.6.
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