Help with geometric sequences and series please!! Need to know how to solve this problem!
whats the problem
sorry it wasnt posting before!
I am really lost on how to solve it. do you know how to do questions like this?
@hartnn are you able to help with this?
@Abhisar any help?
@dan815 sorry for just tagging random people but i cant figure it out!
ok
u can factor out the 4
sum 4* 2^i=4*sum 2^i sum 2^i = 2+4+8....+2^9+2^10 2*sum 2^i-sum2^i = 2^11-2 sum2^i(2-1)=2^11-2 sum2^i=2^11-2 4*sum2^i=4*(2^11-2)
im not sure thats what we are learning hahaha that looks very different
i can go step by step
if u want to learn
we usually put it into a formula like the sum of infinite series
or sum of finite series
like these.
let S be that expression they gave u S=4*2^1+4*2^2+4*2^3....+4*2^10
does this make sense so far
oops i attached the wrong picture. but yes somewhat
i am rewriting the summation notation in terms
and since 4=2^2
we can rewrite it as S=4*2^1+4*2^2+4*2^3....+4*2^10 =2^3+2^4+2^5......+2^12
make sense so far?
yes i think im following
sorry my computer has issues with openstudy! got booted off for a second.
here is the picture i was trying to attach before.
okay now we can do a trick here
S=2^3+2^4+2^5......+2^12 2*S=2^4+2^5+2^6....+2^13 2*S-S=2^13-2^3 S(2-1)=2^13-2^3 S=2^13-2^3
okay i believe i get what you are saying. but that cant be my answer can it?
S=a^1+a^2+a^3......+a^k a*S=a^2+a^3+a^4....+2^(k+1) a*S-S=a^(k+1)-a S(a-1)=a^(k+1)-a S=(a^(k+1)-a)/(a-1)
that is the formula u put up there
it comes from the same method
in our case 2 is the geometric factor if the factor is changed to r then u get that same formula
just see if u can figure this out, u can forget the geometric series formula if u understand this http://prntscr.com/5pno2t
is it D?
@cwrw238 any ideas?
@SolomonZelman
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