solve the equation for principal values of X. Express solution in degrees cos x= 3cos x-2
\[2\cos(x)-2=0\] is a good start
can you put some parentheses in so the eq is clear please
that was whats on the worksheet hun
so next it would be 2 cos x= 2?
yes
I'm sure there are some parentheses around the inside of the cosine, ie is it cosine(x-2) or is it cos(x)-2
and then divided by two?
so cos x=1?
so im confused dose x= 0, 180, 360, or 540 degrees?
cos(180)=-1 not 1 cos(540)=-1 not 1
so its 360 or 0?
well there are infinitely many solutions
also what does principal values mean here?
yea i got that but my teacher wants one
i have no idea, that's one of the reasons Im confused
can't help you if you don't tell me what principal values mean
it is probably 0 though
a principal value is a value along one branch of the function. but ill go with 0
@misty1212 what the heck does that definition mean? what is a branch of a function?
haha 0 was correct i checked with my older brother no worries
I still want to know what branch of a function means
lol
its a branch of a function. if you graph a function a piece between two points on the graph would be a branch of the function, at least that's how i would look at it logically then again math is rarely logical
Well it is definitely suppose to be logical. But I think you meant this for the definition of principal values: For sin(x)=a, it is a number x between -90 deg and 90 deg (including endpoints). For cos(x)=a, it is a number x between 0 and 180 deg (including endpoints).
probably means the answer on the interval \[[0,2\pi)\]
so in this case you pick \(x=0\)
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