Find the lengths of the diagonals of this trapezoid
Well I previously posted to use the distance formula but then you closed it right after.
1. This is an isosceles trapezoid, so the diagonals are congruent. 2. Use the distance formula to find the length using the given coordinates.
In case you don't remember, this is the distance formula: \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
A diagonal is line segment that goes from one vertice to another non-adjacent vertice.
I didnt even take notice to your reply @freckles but heres what i got 40 + 80 + 110 + 4th angle = 360 4th angle = 130 130 + x = 180 x = 50
what is x? And why do we need to do anything with the angles?
We are just finding the distance between (a,0) and (-b,c)
@BeSimple you do not know any of the angles in this case - so I don't know where you got 40,80,100 from all you know are 4 points. They diagram is not 'to scale' and could look like either of the following|: |dw:1420671594391:dw| the points (b,c) and (-a,0) are sufficient to define the lengths as given by the formula above.
|dw:1420671880915:dw|
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