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log x- log (x-2)= 4 both logs have a base of 2 find x, show steps
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the answer is 32/15 but i keep getting no solution
\[\log_2\left(\frac{x}{x-2}\right)=4\] is how you want to begin
\(\large\color{teal}{ \log_2x-\log_2(x-2)=4 }\) \(\large\color{teal}{ \log_2x=4+\log_2(x-2) }\) \(\large\color{teal}{ \log_2x=4\times \log_22+\log_2(x-2) }\) \(\large\color{teal}{ \log_2x= \log_22^4+\log_2(x-2) }\) continue....
then write is in equivalent exponential form
\[\frac{x}{x-2}=2^4\] is the exponential form
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or better yet \[\frac{x}{x-2}=16\]
solve that for \(x\)
you good with that ? that is how you are going to get the \(\frac{32}{15}\) that you know is the answer
yeah, thanks
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