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Mathematics 10 Online
OpenStudy (anonymous):

Really easy!! Simplify the expression!

OpenStudy (anonymous):

OpenStudy (anonymous):

for some reason i am confused on the bottom half and how they managed to get x-8 on the bottom.

OpenStudy (loser66):

64 =8^2 hence \(64-x^2 = 8^2-x^2=(8+x)(8-x)\)

OpenStudy (anonymous):

Okay, is the answer A then?

OpenStudy (loser66):

nup

OpenStudy (anonymous):

okay great thank you!

OpenStudy (anonymous):

oh, it was wrong! haha

OpenStudy (loser66):

Nope, A is not the correct one.

OpenStudy (anonymous):

what was the answer then...i dont know why this question is so confusing for some reason.

OpenStudy (loser66):

You confuse me also. I think you want to study, not just the answer. But it seems I am wrong. hehehe

OpenStudy (anonymous):

haha yes i do want to study. i have a hard time with factoring and these questions.

OpenStudy (anonymous):

i would like to know how to solve them...im not just looking for the answer.

OpenStudy (anonymous):

D.

OpenStudy (anonymous):

this question as well. the farthest i can get it 6(x-4). i cant seem to factor the bottom half. what would you do?

OpenStudy (anonymous):

thank you Alli! i figured it was.

OpenStudy (acxbox22):

factor the top 5x-40 5(x-8) now factor the bottom 64-x^2=-x^2+64=-(x^2-64)=-(x-8)(x+8) like @Loser66 said this leaves 5(x-8)/-(x-8)(x+8) now (x-8) cancels out

OpenStudy (anonymous):

thank you @acxbox22!! that makes much more sense. so for the picture i just attached, the bottom would be factored into -(x^2+16) and then -(x-4) (x+4)?

OpenStudy (acxbox22):

yes good job! you can just factor out a negative one and life becomes easier

OpenStudy (anonymous):

hahah okay awesome. thank you! i always got stuck i didnt know you could just factor out the negative one.

OpenStudy (anonymous):

C for the second one.

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