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Mathematics 18 Online
OpenStudy (anonymous):

Random Variables and Distributions MATH HELP PLZ!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

For the first part: A frequency distribution is a valid probability distribution if all the probabilities add up to 1.

OpenStudy (mathmate):

Hints: 1. probability distributions never go negative, zero sometimes. 2. The integral (or summation) of the distribution over its domain always equals 1.

OpenStudy (mathmate):

Part 2: Integrate or sum over given interval to get the probability of X\(\in\)given interval.

OpenStudy (anonymous):

@DanJS

OpenStudy (mathmate):

Q3: E(X)=\(\sum x p(x)\) or \(\int x p(x) dx\) depending on whether distribution is discrete or continuous.

OpenStudy (mathmate):

Q4. P(succeeds one throw)=0.65=p Use either the binomial coefficients or the multiplication rule to calculate the probability of succeeding 0,1 or 2 throws out of two free throws. Remember that the probabilities must add up to one, because the domain is {0,1,2}.

OpenStudy (mathmate):

Q5. Assuming the figure shows the complete distribution, i.e. probability is 0 elsewhere, then P(X<27) is the ratio of the area below 27 over the total area.

OpenStudy (mathmate):

Q6. similar to Q5.

OpenStudy (mathmate):

Calculate Z=\(\dfrac{X-\mu}{\sigma}\) where \(\mu=mean\) and \(\sigma=standard~deviation\) X=280, \(\mu=290\), and \(\sigma=10\) Look up the normal probability distribution table (left tail) for the calculated Z for P(X<280)

OpenStudy (mathmate):

Q8. Similar to Q7.

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