Question

PRE CALC QUESTIONS (2) HELP!!!! WILL MEDAL AND FAN

Answer 1

Do you know how to write the notation for \(i^2\)?

Answer 2

No @Jhannybean

Answer 3

\[\sum_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}\]

Answer 4

Therefore \[\sum_{i=1}^5i^2 =\frac{5(5+1)(2(5)+1)}{6}\]\[\sum_{i=1}^3 i^2 = \frac{3(3+1)(2(3)+1)}{6}\]

Answer 5

Can you simplify and evaluate these fractions?

Answer 6

would you combine like terms, like in the first one, its like 5(5+1)(2(5)+1) it would be 5(5+1)(2)/6 ? @Jhannybean

Answer 7

but wait , what would the difference be in the first one?

Answer 8

@Jhannybean

Answer 9

[5(6)(11)]/6 = ?

[3(4)(7)]/6 = ?

Answer 10

Don't make it harder than it needs to be :P

Answer 11

oh wait okay, so, the first one is 55 and the secon one is 14 and the difference is 41 @Jhannybean

Answer 12

yes )