a − 3b = 9 a = b − 3 What is the solution to the set of equations in the form (a, b)?
Is this slope intercept?
or what are you looking for exactly?
coordinates
do you think you know the answer
a=9+3b a=b-3
a - 3b = 9 a = b - 3 so sub in b - 3 in for a in the 1st equation (b - 3) - 3b = 9 -- combine like terms -2b - 3 = 9 --- add 3 to both sides -2b = 9 + 3 -2b = 12 b = 12/-2 b = -6 a = b - 3 a = -6 - 3 a = -9 check.. a - 3b = 9 -9 - 3(-6) = 9 -9 + 18 = 9 9 = 9 (correct) so a = -9 and b = -6
substitute 1st eqn into 2nd eqn
the choices are (−9, −6) (−4, −3) (−6, −3) (−9, −7)
(-9,-6)
how did you get that
I did the entire problem up above ^^. Check it out and see if you have any questions ?
Basically, your dealing with a substitution problem
still dont understand
y = x + 14 y = 3x + 2
y = x + 14 y = 3x + 2 2 ways to do this.. (1) y = x + 14...so sub in x + 14 in for y in the other equation x + 14 = 3x + 2 x - 3x = 2 - 14 -2x = - 12 x = 6 y = x + 14 y = 6 + 14 y = 20 OR (2) y = 3x + 2....so sub in 3x + 2 in for y in the other equation 3x + 2 = x + 14 3x - x = 14 - 2 2x = 12 x = 6 y = 3x + 2 y = 3(6) + 2 y = 18 + 2 y = 20 either way you do it, the answers are the same...x = 6 and y = 20 or (6,20)
sorry but I have to go now...kinda lost track of time. I might be back on later...
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