a water balloon is tossed in the air with an upward velocity of 25ft/s. the height h(t)in ft after t seconds is given by the function h(t)=-16^2+25t+3. 1.,After how many seconds will the balloon hit the ground? (hint: Use the quadratic formula) 2.,What will the height be at t = 1 second? please help
Hi What do you need help with today :)
@trinajoy um this question please im having trouble find out the second question the first
btw what grade it this
why?
To find out how many seconds it would take until the balloon hits the ground, you would use the quadratic formula: −b±b2−4ac−−−−−−−√2a −162+25t+3=0−25±625+192−−−−−−−−√−32−25±817−−−√−32 x = 1.674 seconds (other solution is negative) Same thing for t = 1 second, except the equation is equal to 1 instead of 0: −162+25t+3=1−162+25t+2=0−25±625+128−−−−−−−−√−32−25±753−−−√−32 x = 1.638 (other solution is negative) 0 commentsAdd a Comment
that's the answer to the second question (8th g)
@london9321 you see the bottom one that is the answer to the second question I.638 is the answer to the second question
thank you sooo much @trinajoy
np btw are you new to study island @london9321
if so \bbox[8pt, pink,border:5pt solid red ]{\color{black}{\LARGE\cal~\bigstar\heartsuit\dagger Welcome~to~OpenStudy!\bigstar\heartsuit\dagger{{\cal\color{#872af0}{\hspace-274.5pt{\bigstar\heartsuit\dagger Welcome~to~OpenStudy!\bigstar\heartsuit\dagger}}}}~~}}
if you are new to open study here
\bbox[8pt, pink,border:5pt solid red ]{\color{black}{\LARGE\cal~\bigstar\heartsuit\dagger Welcome~to~OpenStudy!\bigstar\heartsuit\dagger{{\cal\color{#872af0}{\hspace-274.5pt{\bigstar\heartsuit\dagger Welcome~to~OpenStudy!\bigstar\heartsuit\dagger}}}}~~}}
yea im knew ??
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