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OpenStudy (highschoolmom2010):
\[\frac{ \sin ^2\theta }{ 1- \cos \theta }\]
OpenStudy (anonymous):
GIMME a second.. ill figure it out
OpenStudy (anonymous):
i just tryed on my calculator it didnt work it just said syntax error
OpenStudy (anonymous):
is is 0/0!
OpenStudy (anonymous):
first, Simplify 1- cos2 Θ= sin2Θ
We know the expression a2 - b2 = (a+b)( a- b)
Similarly, write the left hand side of the equation as (1+cos Θ)(1-cos Θ)
so the whole thing can be written as (1+cos Θ)(1-cos Θ)= Sin2 θ
Divide both sides by (1-cos Θ)
-----> (1+cos Θ) = (Sin2 θ)/ (1- cos θ)
Therefore, if the original question is 1- [(sin2Θ) / (1-cos Θ)] ,
then your answer will be 1 -(1+cos Θ) = - cos Θ
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OpenStudy (anonymous):
Then ig im right
OpenStudy (anonymous):
\[\sin(0^{2}= 0 and 1-\cos(0= 0\] so there for is is 0/0
OpenStudy (anonymous):
how ol are you kingthunder???
OpenStudy (highschoolmom2010):
\[\sin \theta \]
\[1+ \cos \theta\]
\[\frac{ 1+ \sin \theta }{ \cos \theta }\]
\[\frac{ 1- \sin \theta }{ \cos \theta }\]
these were my choices
OpenStudy (anonymous):
@MayaBells01 how old am i?
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OpenStudy (anonymous):
and its the third one @highschoolmom2010
OpenStudy (anonymous):
Nvm
OpenStudy (highschoolmom2010):
thanks @KingThunder314 &@Demonx341
OpenStudy (anonymous):
he is correct :D
OpenStudy (anonymous):
@MayaBells01 text meh
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