simplify the trigonometric expression
\[\frac{ \sin ^2\theta }{ 1- \cos \theta }\]
GIMME a second.. ill figure it out
i just tryed on my calculator it didnt work it just said syntax error
is is 0/0!
first, Simplify 1- cos2 Θ= sin2Θ We know the expression a2 - b2 = (a+b)( a- b) Similarly, write the left hand side of the equation as (1+cos Θ)(1-cos Θ) so the whole thing can be written as (1+cos Θ)(1-cos Θ)= Sin2 θ Divide both sides by (1-cos Θ) -----> (1+cos Θ) = (Sin2 θ)/ (1- cos θ) Therefore, if the original question is 1- [(sin2Θ) / (1-cos Θ)] , then your answer will be 1 -(1+cos Θ) = - cos Θ
Then ig im right
\[\sin(0^{2}= 0 and 1-\cos(0= 0\] so there for is is 0/0
how ol are you kingthunder???
\[\sin \theta \] \[1+ \cos \theta\] \[\frac{ 1+ \sin \theta }{ \cos \theta }\] \[\frac{ 1- \sin \theta }{ \cos \theta }\] these were my choices
@MayaBells01 how old am i?
and its the third one @highschoolmom2010
Nvm
thanks @KingThunder314 &@Demonx341
he is correct :D
@MayaBells01 text meh
Sumbody text meh
i will
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