Find the polynomial equation of least degree with roots -3, 0, and 3
Is this Pre-Calculus?
yes @KingThunder314
The polynomial equation of least degree with roots \(\large\color{slate}{ \color{red}{a}, \color{green}{b}, \color{blue}{c} }\) would be written as: \(\large\color{slate}{ f(x)=(x-\color{red}{a})(x-\color{green}{b})(x-\color{blue}{c})}\)
so the answer would be x^3+x^2+3x-9=0? @SolomonZelman
For example, ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ roots \(\large\color{slate}{ \color{red}{4}, \color{green}{-3}, \color{blue}{5} }\) polynomial of least degree \(\large\color{slate}{ f(x)=(x-\color{red}{4})(x+\color{green}{3})(x-\color{blue}{5})}\) ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ roots \(\large\color{slate}{ \color{red}{-2}, \color{green}{6}, \color{blue}{-10} }\) polynomial of least degree \(\large\color{slate}{ f(x)=(x+\color{red}{2})(x-\color{green}{6})(x+\color{blue}{10})}\)
let me check
nope, it is incorrect.
Was I close?
@SolomonZelman
can you first write the f(x) in a similar to mine, form?
f(x)=(x+3)(x-0)(x-3) @SolomonZelman
yes that is right
(x-0) is same as x, correct?
yes
\(\large\color{slate}{ f(x)=x(x-3)(x+3) }\)
Then FOIL?
Lets focus on the \(\large\color{slate}{ (x-3)(x+3) }\) part for now. The difference of squares rule: \(\large\color{slate}{ (a-b)(a+b)=a^2-b^2 }\) Apply the difference of squares to the: \(\large\color{slate}{ (x-3)(x+3) }\) .
\(\large\color{slate}{ (x-3)(x+3) }\) becomes?
x^3-9x=0 would be the right answer right?
yes
the function would be: \(\large\color{slate}{ f(x)=x^3-9x }\) just the polynomial is: \(\large\color{slate}{ x^3-9x }\) (it is all same, but in different form)
You are very smart that you grabbed it....:)
Thank you for the help! @SolomonZelman
Sure, yw!
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