Question

Help with trig pls

Answer 1

so it would \[\frac{ 1 }{ \sqrt5 }\]

Answer 2

because sin is opposite/hypotenuse

Answer 3

yes it is indeed \(\huge \dfrac{1}{\sqrt{5}}\) but still options are correct

Answer 4

Well Im confused with the options

Answer 5

how it involves \[2\sqrt5\]

Answer 6

the options are just cleverly modified to confuse the students

\(\large\tt \begin{align} \color{black}{hint:\hspace{.33em}\\\dfrac{1}{\sqrt{2}}\hspace{.33em}\\
=\dfrac{1\times \sqrt{2}}{\sqrt{2}\times \sqrt{2}}\hspace{.33em}\\}\end{align}\)

Answer 7

so one of the sqrt of 2s would cancel leavin 1/sqrt2

Answer 8

yes that could happen but also this could happen

\(\large\tt \begin{align} \color{black}{hint:\hspace{.33em}\\\dfrac{1}{\sqrt{2}}\hspace{.33em}\\
=\dfrac{1\times \sqrt{2}}{\sqrt{2}\times \sqrt{2}}\hspace{.33em}\\
=\dfrac{\sqrt{2}}{2}\hspace{.33em}\\
}\end{align}\)

Answer 9

does it helps

Answer 10

Could you explain a bit how it ends like that ?

Answer 11

Oh nevermind

Answer 12

i just thinking wrong

Answer 13

well
\(\large\tt \begin{align} \color{black}{\sqrt{2}\times \sqrt{2}=2\hspace{.33em}\\~\\
\text{just like }\\~\\
\sqrt{4}\times \sqrt{4}=2\times 2=4\hspace{.33em}\\~\\
}\end{align}\)

Answer 14

still stuck ?

Answer 15

\[\frac{ 1*\sqrt2 }{ \sqrt2 * \sqrt2 }=\frac{ \sqrt2 }{ \sqrt4 }=\frac{ \sqrt2 }{ 2 }\]

Answer 16

No I was just thinking wrong :p

Answer 17

yes thats correct !

Answer 18

so which option is correct ?

Answer 19

so then \[\frac{ \sqrt10 }{ 2 }=\frac{ 2\sqrt5 }{ 2 }\]

Answer 20

?

Answer 21

u found
\(\large\tt \begin{align} \color{black}{\sin \theta =\dfrac{1}{\sqrt{5}}\hspace{.33em}\\}\end{align}\) right ?

Answer 22

and this is correct just u have to modify it as i showed u

Answer 23

I thought you would recipricole for some reason

Answer 24

no i just have to change \(\large \sqrt{5}\) to \(\large 5\) in denominator

Answer 25

as i changed in \(\large \dfrac{1}{\sqrt{2}}\)

Answer 26

so sqrt5 x sqrt5?

Answer 27

yes multiply both numerator and denominator by
\(\huge \sqrt{5}\)

Answer 28

so then would we combine the two together now?

Answer 29

yes

Answer 30

so \[\frac{ 1 }{ 5 }*\frac{ \sqrt2 }{ 2 }=\frac{ \sqrt2 }{ 10 }\]

Answer 31

lol no why are u putting \(\sqrt{2}\) here i showed that as example

Answer 32

see if it makes sense

\(\large\tt \begin{align} \color{black}{\dfrac{1}{\sqrt{5}}\\~\\
\dfrac{1\times \sqrt{5}}{\sqrt{5}\times \sqrt{5}}\\~\\
\dfrac{ \sqrt{5}}{5}\\~\\
\hspace{.33em}\\}\end{align}\)

Answer 33

*facepalm*

Answer 34

i see face palm lol

Answer 35

lool sorry im still getting use to all this ._. this is like my first trig chapter in precal

Answer 36

even though it was just me forgetting once again lool

Answer 37

so which option is correct

Answer 38

\[\frac{ \sqrt5 }{ 5 }*\frac{ \sqrt2 }{ 2 }=\frac{ 2\sqrt5 }{ 10 }\frac{ \sqrt5 }{ 5 }\]

Answer 39

?

Answer 40

o.o did i do it wrong again s:

Answer 41

look at my solution

\(\large\tt \begin{align} \color{black}{\dfrac{1}{\sqrt{5}}\\~\\
\dfrac{1\times \sqrt{5}}{\sqrt{5}\times \sqrt{5}}\\~\\
\dfrac{ \sqrt{5}}{5}\\~\\
\hspace{.33em}\\}\end{align}\)

Answer 42

and see the options now

Answer 43

oh so we only had to focus on 1/sqrt5 then

Answer 44

yes :)

Answer 45

i hope u got the soln

Answer 46

so this would be d then?

Answer 47

whiich option is

\(\huge \dfrac{\sqrt{5}}{5}\)

Answer 48

d

Answer 49

are u sure its \(\huge d\)

Answer 50

lool As im looking at another problem

Answer 51

*facepalm* once again

Answer 52

its b

Answer 53

i think its \(\huge b\)

Answer 54

Yehhh you are right xD

Answer 55

yes m right

Answer 56

yeh was looking at problem 3 when this is 2 lool

Answer 57

lol

Answer 58

Thanks for the help :D