Question

I forgot how to do this?? Solving for variable?

Answer 1

your sexy pepsi

Answer 2

well you have to plugin v

Answer 3

\[\frac{v+2}3=\frac{15}{v-2}\]
multiplying by the denominators
\[(v-2)\times(v+2)=3\times15\]

Rearrange this into the general form of
A Quadratic Equation\[ax^2+bx+c=0\]
and use the
The Quadratic Formula\[x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 4

are you trying to make the equation true???@joejoldin

Answer 5

@joejoldin

Answer 6

@andrewhaze yes

Answer 7

@JoeJoldin yes what the equation has to be true

Answer 8

@UnkleRhaukus Which parts of the equation go in the quadratic formula?

Answer 9

have you got the equation into the form
\[av^2+bv+c=0\]
yet?

Answer 10

@UnkleRhaukus I haven't

Answer 11

Rearrange
\[(v-2)\times(v+2)=3\times15\]
until it is of the form
\[av^2+bv+c=0\]

Answer 12

2v^2 + 2v + 3 = 15? @UnkleRhaukus

Answer 13

\[(\overbrace{\overbrace{\color{orange}a
+\underbrace{\color{cornflowerblue}b)(\color{seagreen}c}_{\text{Inside}}}^{\text{First}}
+\color{brown}d}^{\text{Outside}})
=%unklerhaukus
\overbrace{\color{orange}a\color{seagreen}c}^\text F
+\overbrace{\color{orange}a\color{brown}d}^\text O
+\underbrace{\color{cornflowerblue}b\color{seagreen}c}_\text I
+\underbrace{\color{cornflowerblue}b\color{brown}d}_\text L\\
\quad\quad \underbrace{\qquad\quad}_{\text{Last}}\]

Answer 14

still not sure @UnkleRhaukus

Answer 15

\[(\color{orange}v\color{cornflowerblue}{-2})(\color{seagreen}v+\color{brown}2)= (\color{orange}v\times \color{seagreen}v)+(\color{orange}v\times\color{brown}2)+(\color{cornflowerblue}{-2}\times\color{seagreen}v)+(\color{cornflowerblue}{-2}\times\color{brown}2)\]

Answer 16

So do I factor them now? @UnkleRhaukus

Answer 17

don't factor, simplify

Answer 18

v^2 = v^3 + 2^2 @UnkleRhaukus ?

Answer 19

. . . what?
No.

Answer 20

@UnkleRhaukus Can you help me then please

Answer 21

use FOIL