Question

Can i get help?!

Answer 1

Yeah?

Answer 2

Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. Be sure to create and name the appropriate geometric figures.

Answer 3

Is there a picture or anything? If not I probably can't help.

Answer 4

no :/

Answer 5

@SolomonZelman @TheSmartOne can you guys please help?

Answer 6

dont worry someone is going to help u

Answer 7

http://learn.mindset.co.za/sites/default/files/resourcelib/emshare-show-note-asset/LXER_Gr12Mathematics_Euclidean%20Geometry%20%28Similarity%29_08Oct2014.pdf

Answer 8

@coolaidpower

From the diagram below, we can say that the points E and F coincide on AC. DF coincides with DE. Since DF is parallel to BC, DE is also parallel BC This is also know as Converse of Basic Proportionality theorem is proved.

Answer 9

Simplify, in
AE / EC = AF/FC

Add 1 on both sides,

(AE / EC) + 1 = (AF/FC) + 1
(AE + EC) / EC = (AF + FC) / FC
AC / EC = AC / FC

EC = FC

This is how the Converse of Basic Proportionality theorem is proved.

Answer 10

too late :/ @Clalgee @sadcute