Find the number of complex roots for each equation:
2x^4+x^3-3x^2+4x-2
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OpenStudy (freckles):
let's try to plug in some possible rational zeros...
when you plug in x=1 do we get 0?
well
2(1)^4+(1)^3-3(1)^2+4(1)-2
2 +1 -3 +4 -2
2+1-3+4-2
3-3+4-2
4-2=2 which is not 0
you can try the other possible rational zeros...
But before we move on did you post the right expression?
OpenStudy (cold3693):
It all equals 0 that, otherwise it's right.
OpenStudy (freckles):
\[2x^4+x^3-3x^2+4x-2=0 \text{ \right ?}\]
OpenStudy (cold3693):
Yes
OpenStudy (freckles):
oh find the number of
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OpenStudy (freckles):
not find the solutions
OpenStudy (freckles):
do you know descartes rule of signs
OpenStudy (cold3693):
No, it wasn't in our curricular so it was never taught.
OpenStudy (freckles):
ok well if you consider a real number also a complex number which it is
then at max there should be 4 since the degree of the polynomial is 4
OpenStudy (freckles):
That is all I can see to do since you don't know Descartes's rule of signs
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