Find the number of complex roots for each equation: 2x^4+x^3-3x^2+4x-2
let's try to plug in some possible rational zeros... when you plug in x=1 do we get 0? well 2(1)^4+(1)^3-3(1)^2+4(1)-2 2 +1 -3 +4 -2 2+1-3+4-2 3-3+4-2 4-2=2 which is not 0 you can try the other possible rational zeros... But before we move on did you post the right expression?
It all equals 0 that, otherwise it's right.
\[2x^4+x^3-3x^2+4x-2=0 \text{ \right ?}\]
Yes
oh find the number of
not find the solutions
do you know descartes rule of signs
No, it wasn't in our curricular so it was never taught.
ok well if you consider a real number also a complex number which it is then at max there should be 4 since the degree of the polynomial is 4
That is all I can see to do since you don't know Descartes's rule of signs
Alright thanks.
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