Question

I have a quick question. I am currently studying for my math semester exam which I will take tomorrow. In the review, I have this question that I got wrong:

They give me the y intercept which is 1500 and a point (2,1600)
The answer is supposed to be: =63x+1500
But I don't understand how, I am pretty sure is something easy but I think I was taught this early on the semester and I have forgotten. Please help?

Answer 1

i assume you are looking for a line with y-int=1500 and a point (2,1600)

Answer 2

you can find the slope
and then use point slope form to find the line

Answer 3

y-int=1500
or in ordered pair form (0,1500)

Answer 4

so find the slope of a line going through (0,1500) and (2,1600)

Answer 5

The equation of a line has the form:

y = mx + b

Here m = slope, b = y intercept.

you are given b = 1500 , but not the slope. so lets plug that in

y = mx + 1500 .

Now plug in the point (2,1600)

1600 = m(2) + 1500

solve for m

Answer 6

\[m=\frac{y_2-y_1}{x_2-x_1}\]

Answer 7

or that way

Answer 8

solving for m :
1600 = m*2 + 1500

1600 - 1500 = 2m
100 = 2m
m = 100/2

Answer 9

Oh I missed that small part of (0,1500) I see

Answer 10

the points given give us the equation
y = 50x + 1500 , not y = 63x + 1500
so theres a typo in the directions

Answer 11

Thank You very much for your help :) I understand now