Question

@DanJS

Answer 1

This one would be easier to integrate over dy

Answer 2

y from 0 to 1, then y from 1 to 4

Answer 3

put your equations in terms of x = ....

Answer 4

Or if you wanted to integrate over x instead still....
you would need to do x from 0 to 1, of the green line 4 - 3x
then
subtract the integral from 0 to 1 of the red line y = x

Answer 5

Both of those could be done using the simple area of a triangle formula. since they are all straight lines. but

Answer 6

that could be a way to check if your integrals are correct, find the area of the region using area of triangle = half base times height

Answer 7

the region in question has a base of 4 and a height of 1, area is half of 4 times 1, or Area = 2

Answer 8

Here is the integral...

Answer 9

\[\int\limits_{0}^{1}(4-3x)dx - \int\limits_{0}^{1}(x) dx \]

Answer 10

Which evaluates to the same as the area using the triangle formula, 2

Answer 11

U understand, or what dont make sense?

Answer 12

(4-3x)??

Answer 13

ohhh nevermind

Answer 14

yeah i think i understand(:

Answer 15

i got 4 before because i didnt divide it by 2

Answer 16

You take the whole area under the green line from 0 to 1, then subtract that little area under the red line from 0 to 1

Answer 17

The integrals work out to be 2
so does the same thing using triangle formula

Answer 18

thanks(:

Answer 19

taking me back to calc 1 days years ago. lol these are kinda fun to do

Answer 20

Help me i got 25 questions