Find the coordinates of the center of the following circle.
(x - 5)² + (y + 3)² = 25
(-5, 3)
(5, -3)
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OpenStudy (xapproachesinfinity):
if you have \((x-a)^2+(x-b)^2=r^2\)
the center is (a,b) and the radius is r
OpenStudy (xapproachesinfinity):
look at you circle equation and see what you need to do
OpenStudy (xapproachesinfinity):
my mistake it should be with y-b not x-b
OpenStudy (xapproachesinfinity):
\((x-a)^2+(y-b)^2=r^2\) like this
now it looks like your equation look for a and b
OpenStudy (xapproachesinfinity):
do you get it
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OpenStudy (anonymous):
not really
OpenStudy (xapproachesinfinity):
every circle equation is written like \((x-a)^2+(y-b)^2=r^2\)
this is a general circle equation with center (a,b)
in your case you have \((x-\color{red}{5})^2+(y\color{red}{+}\color{blue}{3})^2=25\)
OpenStudy (xapproachesinfinity):
a=5 and b=-3 in your case
OpenStudy (xapproachesinfinity):
since we have y+3
that means y-(-3)
that's b=-3
so the center is (5,-3)
OpenStudy (anonymous):
ohh got it thnx
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OpenStudy (xapproachesinfinity):
welcome!
try finiding the center of this circle \(x^2+(y-2)^2=36\)