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Help with simplifying?
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can u factorize \(b^2 + b - 2 \)?
u can find \( b^2 + b - 2 = (b+2)(b-1) \)?
putting it in that expression will give us \(\Large \frac{ 7b-1 }{ (b+2)(b-1) } - \frac{ 6 }{ b-1 }\)
so u can say \( \Large \frac{ 7b-1 }{ (b+2)(b-1) } - \frac{ 6 }{ b-1 } = \frac{7b-1}{(b+2)(b-1)}- \frac{6(b+2)}{(b-1)(b+2)} \)
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can u find it now? @RockerChic8
@PFEH.1999 I think, is it c?
no ;)
what does the last expression i gave u equal to ?
@PFEH.1999 1b-3 ____ b^2 +1 ?
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@PFEH.1999 ?
yes so what is the answer u think?
@PFEH.1999 Looks sort of like B
it would be \(\large \frac{b-3}{(b-1)(b+2)} \)
and forgot to plug in 13 instead of 3 , typo :| so doesn't seem D is the answer?
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got it?
@PFEH.1999 thanks
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