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Mathematics 7 Online
OpenStudy (anonymous):

Help with simplifying?

OpenStudy (anonymous):

OpenStudy (anonymous):

can u factorize \(b^2 + b - 2 \)?

OpenStudy (anonymous):

u can find \( b^2 + b - 2 = (b+2)(b-1) \)?

OpenStudy (anonymous):

putting it in that expression will give us \(\Large \frac{ 7b-1 }{ (b+2)(b-1) } - \frac{ 6 }{ b-1 }\)

OpenStudy (anonymous):

so u can say \( \Large \frac{ 7b-1 }{ (b+2)(b-1) } - \frac{ 6 }{ b-1 } = \frac{7b-1}{(b+2)(b-1)}- \frac{6(b+2)}{(b-1)(b+2)} \)

OpenStudy (anonymous):

can u find it now? @RockerChic8

OpenStudy (anonymous):

@PFEH.1999 I think, is it c?

OpenStudy (anonymous):

no ;)

OpenStudy (anonymous):

what does the last expression i gave u equal to ?

OpenStudy (anonymous):

@PFEH.1999 1b-3 ____ b^2 +1 ?

OpenStudy (anonymous):

@PFEH.1999 ?

OpenStudy (anonymous):

yes so what is the answer u think?

OpenStudy (anonymous):

@PFEH.1999 Looks sort of like B

OpenStudy (anonymous):

it would be \(\large \frac{b-3}{(b-1)(b+2)} \)

OpenStudy (anonymous):

and forgot to plug in 13 instead of 3 , typo :| so doesn't seem D is the answer?

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

@PFEH.1999 thanks

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