Don't understand how to work out this problem, any help is greatly appreciated
Here's the problem attached
Ik it's small but just zoom in to see it
do you know that the radius \(\perp\) the cord at its middle point?
the radius is perpendicular to the cord at it's middle point? Ok so what exactly is the cord again?
|dw:1420772181757:dw|
hence, if AB =19.2 , then you can apply pythagorean to get x, right?
would be 9.6^2+x^2=?
=12^2
how did you get 12^2?
diameter =24 --> radius =12
|dw:1420772429604:dw|
Okay so it would be 9.6^2+x^2=12^2?
yup
Cool Thanks mind helping with a few more?
not sure but if i can, i will but Mersi here, she is the best in geometry, not worry :)
thanks appreciate it
so how did you get 19.2 when it only said 16 on that last problem?
don't get what you mean
19.2 is given, I don't get it from anywhere
oh yeah my bad XD
And what is the "last problem"? I saw just only 1 problem
Here it is
hey, it is exactly the same, just diameter =16 and the chord = 25.6
so the diameter isn't longer than 16?
nope, exactly 16 --> radius =8
hold on
awesome
it can be radius =16, let me check
Yes, in this case, it is radius =16
So the diameter is 32 right
how can we know? we know it because the radius is the hypotenuse in the right triangle, and it MUST be longer than the leg which is \(\dfrac{25.6}{2}=12.8\)
okay I get it
if it is 8, we don't have hypotenuse > the leg That is the way to check in the case they give us an ambiguous information
Cool I don't wanna bug you so can you help with this 1 last problem?
we have formula to find it out, the ratio : \(\dfrac{AB}{AD}=\dfrac{AC}{AE}\) only one term you don't know is AD, quite easy, right?
Join our real-time social learning platform and learn together with your friends!