HELP QUICKLY PLEASE!!! http://nimb.ws/hWiC3K
Yes, you are correct on b)
to c) just let it =125, then solve for t
ur good CX
I mean \(64+e^{-0.5t}=125\)
Thanks guys :)! But I am a bit bit confuse on how to find t. 64+144e^(-0.5t)=125 I got it's just the e^(-0.5t)
oh, mistake hehehe ok,
-64 both sides, get what?
it seems someone will give you the answer for free. OOOOOOOOOOOK, good luck
You take ln of both sides to get rid of the e^(x), because ln(e^(x)) = x
If that helps...
lol it's okay . and 125-68= 58=144e^(0.5t) right?
It does thanks @aleroth :)
:) You are on the right path.
Except 125-68 = 57
Ah a mistype :P, Oh okay so I subtract 144 from both sides and divide -0.5t to find t?
Not quite. From here: 57=144e^(0.5t) Divide both sides by 144: 57/144 =144*e^(0.5t)/144 Then take the logarithm of both sides: ln (57/144) = ln(e^0.5t) = 0.5t Then divide both sides by 0.5 (or multiply by 2) to get t alone: 2*ln(57/144) = t
I made a mistake the 0.5t is -0.5t would that change the answer?
Oh right, it would look like this instead: Divide both sides by 144: 57/144 =144*e^(-0.5t)/144 Then take the logarithm of both sides: ln (57/144) = ln(e^-0.5t) = -0.5t Then divide both sides by 0.5 (or multiply by 2) to get t alone: 2*ln(57/144) = -t Multiply both sides by -1: -2*ln(57/144) = -(-t) = t
Ah okay would 1.8535 be the answer..?
Yeah, seems that right.
Thank you so much ! You are Brilliant !!!
Glad to help :D
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